accounts

来自「linux脚本编程的例子」· 代码 · 共 9 行

for i in $(cut -f 1,3 -d: /etc/passwd) ; do
   array[${i#*:}]=${i%:*}
done

echo "User ID $1 is ${array[$1]}."
echo "There are currently ${#array[@]} user accounts on the system."