📄 longbeige-cpp.txt
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#include<iostream.h>
#include<stdio.h>
#include<math.h>
float f(float x)
{ if(x==0)
return 1;
else return sin(x)/x;
}
float Romberg(float a,float b,float (*f)(float),float e)
{
int n=1,k;
float h=b-a,x,S;
float T1,T2,S1,S2,C1,C2,R1,R2;
T1=(b-a)/2*((*f)(a)+(*f)(b));
while(1)
{
S=0;
for(k=0;k<=n-1;k++)
{
x=a+k*h+h/2;
S+=(*f)(x);
}
T2=(T1+S*h)/2;
if(fabs(T2-T1)<e)
return T2;
S2=T2+(T2-T1)/3.0;
if(n==2)
{
T1=T2;
S1=S2;
h/=2;
n*=2;
continue;
}
C2=S2+(S2-S1)/15;
if(n==4)
{
C1=C2;
T1=T2;
S1=S2;
h/=2;
n*=2;
continue;
}
R2=C2+(C2-C1)/63;
if(n==8)
{
R1=R2;
C1=C2;
T1=T2;
S1=S2;
h/=2;
n*=2;
continue;
}
if(fabs(R2-R1)<e)
return R2;
R1=R2;
C1=C2;
T1=T2;
S1=S2;
h/=2;
n*=2;
}
}
void main()
{
float a,b;
float e=5e-6;
cout<<("请输入积分上限\n")<<endl;
scanf("%f",&b);
cout<<("请输入积分下限\n")<<endl;
scanf("%f",&a);
cout<<"R="<<Romberg(a,b,f,e)<<endl; /*在Romberg(a,b,f,e))中a为下限,b为上限,f为所调用子函数,e为误差精度*/
}
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