⭐ 欢迎来到虫虫下载站! | 📦 资源下载 📁 资源专辑 ℹ️ 关于我们
⭐ 虫虫下载站

📄 1.htm

📁 非常不错的网络工程师模拟题目 多做题
💻 HTM
字号:
<html>
<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<script language="JavaScript">
<!--
function MM_preloadImages() { //v2.0
  if (document.images) {
    var imgFiles = MM_preloadImages.arguments;
    if (document.preloadArray==null) document.preloadArray = new Array();
    var i = document.preloadArray.length;
    with (document) for (var j=0; j<imgFiles.length; j++) if (imgFiles[j].charAt(0)!="#"){
      preloadArray[i] = new Image;
      preloadArray[i++].src = imgFiles[j];
  } }
}

function MM_swapImgRestore() { //v2.0
  if (document.MM_swapImgData != null)
    for (var i=0; i<(document.MM_swapImgData.length-1); i+=2)
      document.MM_swapImgData[i].src = document.MM_swapImgData[i+1];
}

function MM_swapImage() { //v2.0
  var i,j=0,objStr,obj,swapArray=new Array,oldArray=document.MM_swapImgData;
  for (i=0; i < (MM_swapImage.arguments.length-2); i+=3) {
    objStr = MM_swapImage.arguments[(navigator.appName == 'Netscape')?i:i+1];
    if ((objStr.indexOf('document.layers[')==0 && document.layers==null) ||
        (objStr.indexOf('document.all[')   ==0 && document.all   ==null))
      objStr = 'document'+objStr.substring(objStr.lastIndexOf('.'),objStr.length);
    obj = eval(objStr);
    if (obj != null) {
      swapArray[j++] = obj;
      swapArray[j++] = (oldArray==null || oldArray[j-1]!=obj)?obj.src:oldArray[j];
      obj.src = MM_swapImage.arguments[i+2];
  } }
  document.MM_swapImgData = swapArray; //used for restore
}
//-->
</script>
<script language="VBScript">
<!--
Dim numa, numb, numc, numd
Public resflag, resultstr, ansnum, exwav(100), exwavnum, mins, secs
resultstr = ""
answerstr = ""
rightnum = 0
mins=minute(now)
secs=second(now)
numa = 1
numb = 1
numc = 5
numd = 0

Sub checkans(tnum)
dim answerstr

  resflag = -1
  answerstr = "正确答案:"
  for i = 0 to ansnum - 1
    if (tnum(i).Value = 1) then
      answerstr = answerstr & chr(asc("A")+i)
      if (tnum(i).checked) then
        if resflag=-1 then resflag = 1
      else
        resflag=0
      end if
    else
      if (tnum(i).checked) then resflag = 0
    end If
  next
  tnum(ansnum).Value = answerstr

End Sub

-->
</script>
<link href="../css/page.css" rel="stylesheet" type="text/css">
<style type="text/css">
<!--
.style1 {font-size: 12px}
body {
	background-image: url(images/beijing.gif);
}
.STYLE2 {font-size: 18px}
-->
</style>
</head>
<body bgcolor="#FFFFFF" leftmargin="0" topmargin="0" bgproperties="fixed" marginwidth = "0" marginheight = "0" class="font14" onLoad="MM_preloadImages('images/chuer/ball_off.gif','#931464069070');MM_preloadImages('images/chuer/ball_off.gif','#931464082530');MM_preloadImages('images/chuer/ball_off.gif','#931464095660');MM_preloadImages('images/chuer/ball_off.gif','#931464104880');MM_preloadImages('images/chuer/ball_off.gif','#931464114770');MM_preloadImages('images/chuer/ball_off.gif','#931464135860')">
<table border="0" cellpadding="0" cellspacing="0" width="100%" height="1504">
  <tr> 
    <td valign="top" width="3%" height="1491"> 
      <!-- This left bar table begin -->
      <br> 
      <!-- This left bar table end-->
      <!-- This navbar content begin -->
    </td>
    <td valign="top" width="97%" height="1491"> 
      <!-- This is main text bar begin -->
      <!-- this table is logo and title begin -->
      <table width="100%" height="1436" border="0" cellpadding="0" cellspacing="0" class="unnamed1">
        <tr> 
          <td width="99%" height="400" border = "0" alt> 
            <form method=POST name=examfrm>
              <p align="center" class="style1">全国计算机技术与软件专业技术资格(水平)考试 <br>
                全真模拟试卷(一)上午试题(考试时间9∶00~11∶30,共150分钟)</p>
              <span class="style1">1.本试卷的试题中共有75个空格,需要全部解答,每个空格1分,满分75分              </span>
              <p class="style1">2.每个空格对应一个序号,有A、B、C、D四个选项,请选择一个最恰当的选项作为解答。<br>
                <br>
                ●在某个计算机系统中,内存地址与I/O地址统一编址,访问内存单元和I/O设备是靠<u> (1) </u>来区分的。</p>
              <p class="style1"> 
                (1)
                <input type=radio name=tba1 Value = 0 >
                A.数据总线上输出的数据<br>
&nbsp;&nbsp;&nbsp;
                 <input type=radio name=tba1 Value = 1>
                B.不同的地址代码 <br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba1 Value =0 >
                C.内存与I/0设备使用不同的地址总线 <br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba1 Value = 0>
                D.不同的指令 </p>
              <table width="100%" border="0" cellspacing="0" cellpadding="0">
                <tr>
                  <td width="13%" valign="top" class="title">
                    <span class="style1">
                    <input name=tba1 type=text id="tba1" size=10 >                  
                    </span></td>
                  <td width="87%" valign="top"><span class="style1" style="text-align:left;"><img src="images/anniu.gif" width="78" height="22" img style="CURSOR: hand" onClick=DisplayOrHidden(T1)></span>
                    <table width="96%" border="0">
                    <tr>
                      <td><p align=left class="style1" style='text-align:left;'><SPAN id=T1 style="BORDER-RIGHT: #ffffff 1px solid; BORDER-TOP: #ffffff 1px solid; DISPLAY: none; BORDER-LEFT: #ffffff 1px solid; COLOR: black; BORDER-BOTTOM: #ffffff 1px solid; FONT-FAMILY: 宋体"><span class="STYLE1" style="font-family: 宋体"><strong>&nbsp;</strong></span><span class="style1">【解析】本题考查的是计算机系统的编址方式,考生必须要了解内存和I/O设备在计算机系统中是如何编址的,并如何区分这些地址。
所谓统一编址,就是将内存和I/O设备的地址放在一个连续的地址空间内,对于内存和不同的I/O设备,它们的地址在这个连续的地址空间内被划分为不同的块。这些地址块有一个范围,对这个范围内的地址进行寻址,则可以访问相应的设备。因此,统一编址的方式是根据不同的地址代码来区分不同的设备。</td>
                    </tr>
                  </table></td>
                </tr>
              </table>
              <p class="style1">●USB是<u> (2) </u>。</p>
              <p class="style1"> 
                (2)
                <input type=radio name=tba2 Value = 0>
                A.并行总线 <br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba2 Value = 0 >
                B.串行总线 <br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba2 Value = 0 >
                C.通用接口<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba2 Value = 1 >
              D.通用串行接口总线</p>
              <table width="100%" border="0" cellspacing="0" cellpadding="0">
                <tr>
                  <td width="13%" valign="top" class="title">
                    <span class="style1">
                    <input name=tba2 type=text id="tba2" size=10 >                  
                    </span></td>
                  <td width="87%" valign="top"><span class="style1" style="text-align:left;"><img src="images/anniu.gif" width="78" height="22" img style="CURSOR: hand" onClick=DisplayOrHidden(T2)></span>
                      <table width="96%" border="0">
                        <tr>
                          <td><p align=left style='text-align:left;'>                
                              <span class="style1"><SPAN id=T2 style="BORDER-RIGHT: #ffffff 1px solid; BORDER-TOP: #ffffff 1px solid; DISPLAY: none; BORDER-LEFT: #ffffff 1px solid; COLOR: black; BORDER-BOTTOM: #ffffff 1px solid; FONT-FAMILY: 宋体"><span class="STYLE1" style="font-family: 宋体"><strong>&nbsp;</strong></span><span class="style1">
【解析】USB 是一种通用串行接口总线。它可连127个设备,占用1 个中断,支持12Mbps数据传输率。</span></td>
                        </tr>
                    </table></td>
                </tr>
              </table>
              <p class="style1">●一个32K×32位的主存储器,其地址线和数据线的总和为<u> (3) </u>根。</p>
              <p class="style1"> 
                (3)
                <input type=radio name=tba3 Value = 0 >
                A.64 <br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba3 Value = 1 >
                B.47 <br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba3 Value = 0 >
                C.48<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba3 Value = 0 >
                D.36</p>
              <table width="100%" border="0" cellspacing="0" cellpadding="0">
                <tr>
                  <td width="13%" valign="top" class="title">
                    <span class="style1">
                    <input name=tba3 type=text id="tba3" size=10 >                  
                    </span></td>
                  <td width="87%" valign="top"><span class="style1" style="text-align:left;"><img src="images/anniu.gif" width="78" height="22" img style="CURSOR: hand" onClick=DisplayOrHidden(T3)></span>
                      <table width="96%" border="0">
                        <tr>
                          <td class="style1"><SPAN id=T3 style="BORDER-RIGHT: #ffffff 1px solid; BORDER-TOP: #ffffff 1px solid; DISPLAY: none; BORDER-LEFT: #ffffff 1px solid; COLOR: black; BORDER-BOTTOM: #ffffff 1px solid; FONT-FAMILY: 宋体"><span class="STYLE1" style="font-family: 宋体"><strong>&nbsp;</strong></span><span class="style1"><span class="style1">
                          【解析】32K×32位的存储器,其数据线需要32根;32K是其容量大小,根据2的n次幂=32×1024可以计算出:n=15。于是至少需要15根地址线,所以,所需的地址和数据线总和为47。 </td>
                        </tr>
                    </table></td>
                </tr>
              </table>
              <p class="style1">●下面关于系统总线的描述中,正确的概念是<u> (4) </u>。</p>
              <P CLASS=style1> 
                (4)
                <input type=radio name=tba4 Value = 0 >
                A.地址信息和数据信息不能同时出现<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba4 Value = 0 >
                B.地址信息和控制信息不能同时出现<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba4 Value = 0>
              C.数据信息和控制信息不能同时出现<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba4 Value = 1 >
              D.两种信息源的代码不能在总线中同时出现</P>
              <table width="100%" border="0" cellspacing="0" cellpadding="0">
                <tr>
                  <td width="13%" valign="top" class="title">
                    <span class="style1">
                    <input name=tba4 type=text id="tba4" size=10 >                  
                    </span></td>
                  <td width="87%" valign="top"><span class="style1" style="text-align:left;"><img src="images/anniu.gif" width="78" height="22" img style="CURSOR: hand" onClick=DisplayOrHidden(T4)></span>
                      <table width="96%" border="0">
                        <tr>
                          <td class="style1"><SPAN id=T4 style="BORDER-RIGHT: #ffffff 1px solid; BORDER-TOP: #ffffff 1px solid; DISPLAY: none; BORDER-LEFT: #ffffff 1px solid; COLOR: black; BORDER-BOTTOM: #ffffff 1px solid; FONT-FAMILY: 宋体"><span class="STYLE1" style="font-family: 宋体"><strong>&nbsp;</strong></span><span class="style1">
【解析】在系统总线中,地址信息、数据信息、控制信息是可以同时出现的。为了便于区分它们,任何两种信息源的代码不能在总线中同时出现。</td>
                        </tr>
                    </table></td>
                </tr>
              </table>
              <p class="style1">●CMM模型将软件过程的成熟度分为5个等级,在<u> (5) </u>使用定量分析来不断地改进和管理软件过程。</p>
              <p class="style1"> 
                (5)
                <input type=radio name=tba5 Value = 1 >
                A.优化级<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba5 Value = 0 >
                B.管理级<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba5 Value = 0>
                C.定义级<br>
&nbsp;&nbsp;&nbsp;
                <input type=radio name=tba5 Value = 0 >
                D.初始级<br>
              </p>
              <table width="100%" border="0" cellspacing="0" cellpadding="0">
                <tr>
                  <td width="13%" valign="top" class="title">
                    <span class="style1">
                    <input name=tba5 type=text id="tba5" size=10 >                  
                    </span></td>
                  <td width="87%" valign="top"><span class="style1" style="text-align:left;"><img src="images/anniu.gif" width="78" height="22" img style="CURSOR: hand" onClick=DisplayOrHidden(T5)></span>
                      <table width="96%" border="0">
                        <tr>
                          <td class="style1"><SPAN id=T5 style="BORDER-RIGHT: #ffffff 1px solid; BORDER-TOP: #ffffff 1px solid; DISPLAY: none; BORDER-LEFT: #ffffff 1px solid; COLOR: black; BORDER-BOTTOM: #ffffff 1px solid; FONT-FAMILY: 宋体"><span class="STYLE1" style="font-family: 宋体"><strong>&nbsp;</strong></span><span class="style1"><span class="style1">
                          【解析】CMM是软件能力成熟度模型,CMM的分级结构可以描述为:

⌨️ 快捷键说明

复制代码 Ctrl + C
搜索代码 Ctrl + F
全屏模式 F11
切换主题 Ctrl + Shift + D
显示快捷键 ?
增大字号 Ctrl + =
减小字号 Ctrl + -