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📄 controlservlet.java

📁 MVC留言
💻 JAVA
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package org.bob.control;import java.io.IOException;import java.io.PrintWriter;import java.util.Enumeration;import java.util.Iterator;import java.util.Map;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;public class ControlServlet extends HttpServlet {	public void destroy() {		super.destroy(); 	}		public void doGet(HttpServletRequest request, HttpServletResponse response)			throws ServletException, IOException {			this.doPost(request, response);	}		public void doPost(HttpServletRequest request, HttpServletResponse response)			throws ServletException, IOException {		  //获得请求的的路径		  String uri=request.getRequestURI();		  //由于我们采用的是请求处理类的方式,来发送请求,所以要截取出类名		  uri=uri.substring(uri.lastIndexOf("/")+1,uri.indexOf(".dao"));		  //将类名存放在request作用域当中		  request.setAttribute("requestName",uri);		  //转发到逻辑处理		  request.getRequestDispatcher("/logic").forward(request,response);	}		public void init() throws ServletException {			}}

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