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📁 美国卡耐基。梅隆大学SSD8课程练习3的答案
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	<TITLE>"SSD8-Exercise3"</TITLE>
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<center> 
Ideal Throughput = buffer size(TCP Buffer Size*8) / round trip time.<BR>
The Round trip time is 2.047ms.
<table width="900" border="1" cellspacing="0" cellpadding="2" align="CENTER"> 
     <tr align="CENTER"> 
<th>TCP Buffer Size(bytes)</th><th>Ideal Throughput(10^6bits/sec)</th><th>Actual Throughput(10^6bits/sec)</th> 
     </tr> 
     <tr align="CENTER"> 
<td>1000</td><td>3.91</td><td>0.04</td> 
     </tr> 
     <tr align="CENTER"> 
<td>2000</td><td>7.82</td><td>48.91</td> 
     </tr> 
     <tr align="CENTER"> 
<td>3000</td><td>11.72</td><td>71.79</td> 
     </tr> 
     <tr align="CENTER"> 
<td>4000</td><td>15.63</td><td>84.82</td> 
     </tr>
     <tr align="CENTER"> 
<td>5000</td><td>19.54</td><td>91.06</td> 
     </tr>
     <tr align="CENTER"> 
<td>6000</td><td>23.45</td><td>91.49</td> 
     </tr>
     <tr align="CENTER"> 
<td>7000</td><td>27.36</td><td>93.64</td> 
     </tr>
     <tr align="CENTER"> 
<td>8000</td><td>31.27</td><td>93.54</td> 
     </tr>
     <tr align="CENTER"> 
<td>24000</td><td>93.80</td><td>93.83</td> 
     </tr>
     <tr align="CENTER"> 
<td>25000</td><td>97.70</td><td>93.48</td> 
     </tr>
</table> 
</center> 
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