main.lst

采用1621控制段式液晶的显示,单片机控制乱序显示及实现银行系统的加密功能

C51 COMPILER V6.12  MAIN                                                                   05/22/2007 20:27:54 PAGE 1   


C51 COMPILER V6.12, COMPILATION OF MODULE MAIN
OBJECT MODULE PLACED IN .\main.OBJ
COMPILER INVOKED BY: D:\Program Files\keil51\C51\BIN\C51.EXE .\main.c LARGE DEBUG OBJECTEXTEND

stmt level    source

   1          #include <panel.h>
   2          #include <1621.h>
   3          #include <STC89C51.H>
   4          #include <stdlib.h>
   5          
   6          static unsigned char  sbuf[100];
   7          static unsigned char key_num[10];
   8          unsigned char   token=0;
   9          unsigned char len=0;
  10          static unsigned int t=5;
  11          void DisplayNum(void)
  12          {
  13   1         unsigned char ADDr[]={0x06,0x04,0x02,0x00,0x0e,
  14   1                               0x10,0x12,0x08,0x0a,0x0c};
  15   1         unsigned char  seg[]={0xdf,0x86,0xbd,0xaf,0xe6,0xeb,0xfb,0x8e,0xff,0xef};//数码管1,2,3,4,5,6,7,8,9,10对
             -应数字显示
  16   1                               //0    1    2    3    4    5     6   7    8     9 
  17   1         unsigned char i,j;
  18   1         
  19   1      int num[]={0,1,2,3,4,5,6,7,8,9};
  20   1               //SMG10  SMG1 SMG2 SMG3 SMG4 SMG5 SMG6 SMG7 SMG8 SMG9  
  21   1      int rn[10];
  22   1      
  23   1      srand((unsigned)t++);//time(&t));
  24   1      for(i=0;i<10;i++)
  25   1      {
  26   2        rn[i]=rand()%10;
  27   2        for(j=0;j<i;j++)
  28   2        {
  29   3           if(rn[i]==rn[j]){i--;j=i;}
  30   3        }
  31   2      }
  32   1       for(i=0;i<10;i++)
  33   1       {key_num[i] = num[rn[i]];}
  34   1         for(i=0;i<10;i++)
  35   1           {
  36   2           Write_1621(ADDr[i],seg[key_num[i]]);
  37   2           }
  38   1      }
  39          
  40          
  41          
  42          void DisplayNum_sequence(void)
  43          {
  44   1      
  45   1      int i;
  46   1      unsigned char ADDr[]={0x06,0x04,0x02,0x00,0x0e,
  47   1                               0x10,0x12,0x08,0x0a,0x0c};
  48   1      unsigned char  seg[]={0xdf,0x86,0xbd,0xaf,0xe6,0xeb,0xfb,0x8e,0xff,0xef};//数码管1,2,3,4,5,6,7,8,9,10对应