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📁 天线方向图程序
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     All parameters are self-explanatory except the last.  Forswept frequency analysis, the program starts at the lowestanalysis frequency, AFlow, and after each iteration increasesthe analysis frequency by a certain amount until it exceeds theupper analysis frequency.  The step size, AFstep, is defined bythe following relation.     AFstep = FMHz * 10 ** (1/AFpowr)where FMHz is the current analysis frequency.  This relation hasthe advantage of providing equally spaced points when frequencyis plotted on a logarithmic scale.  Increasing AFpowr increasesthe resolution.3.  ALGORITHM DEVELOPMENT     Some of the algorithms have already been explained, but forthe sake of clarity, all will be explained here.  There isnothing fantastically difficult about any particular step of thealgorithm, but taken together there are so many topics that itis easy to become confused.     Since the design of the antenna is covered in the book, itwill be omitted here.  Let us begin the discussion knowing thetopology of the design, as if we had an antenna in hand, so thatwe are ready to analyze it.     There are several steps to the analysis of the antenna. First, we must calculate the self and mutual impedances of eachantenna element.  These calculations tell us how each excitedelement interacts with each other element and how well eachantenna radiates.  Next, we need to calculate thecharacteristics of the antenna transmission line.  Thiscalculation accounts for the termination impedance (Zout) aswell as the source impedance (Rs).  It tells us how energypropagates down the transmission lines.  Third, we need to solvefor the currents on each antenna element as well as the inputcurrent (Iin) and voltage (Vin) and the termination current(Iout) and voltage (Vout).  Finally, we calculate the gain,VSWR, and other important parameters.3.1.  SELF AND MUTUAL IMPEDANCES     The self and mutual impedances of radiating elements is asubject of much research.  To understand the basic idea[8],consider several radiating elements located in space.  Nowremove all elements except one, for instance element 1, andexcite it with a current.  The input impedance can be measuredas the ratio of the input voltage over the input current.  Thisis the self impedance denoted Z11.  Now replace one of the otherelements, say element 2, and short its terminals together. Recalculate the input impedance of element 1.  This is themutual impedance denoted Z12 (impedance of element 1 due toelement 2).  Repeat the process for every pair of antennas. (The measurements can be roughly halved, because reciprocityassures us that Z12 = Z21.  This means the resulting matrix issymmetric.)      To obtain very accurate results, finite difference methodsand projection methods, which include moment methods andfinite element methods often are used.  Finite differencemethods approximate the governing differential equations bymathematically dividing the surface into very small segments, thenapproximating a derivative by the equation           f(x2) - f(x1)     df = ---------------              x2 - x1  For projection methods, a set of basis functions which satisfythe boundary conditions are weighted and summed to form anapproximate answer.  For moment methods, the basis functions arevalid for the entire antenna surface.  For finite elementmethods, the basis functions are valid over a small part of theantenna surface.     An alternative approach, and the one used here, assumesthat the current distribution along each antenna variessinusoidally.  This assumption is valid for infinitesimally thindipoles sitting alone in space.  While this assumption is nottotally valid, the approximation is still a good one.     With this assumption, the self and mutual impedances can bewritten as integral equations.  These equations can berecast in terms of the sine and cosine integrals[9][10].  Withthese equations, the symmetric matrix, called ZA in the program,can be found.3.2.  TRANSMISSION LINE ADMITTANCE MATRIX     Next, we must compute the characteristics of the antennatransmission line.  Good documentation can be found in theliterature [6][7][8], although these references cansometimes be hard to find.  Therefore, a summary will bepresented here.  We wish to create the same kind of data for thetransmission line as we did for the self and mutual impedances. That is, we will excite the transmission line with a unitvoltage everywhere an antenna element attaches, one place at atime.  The remaining places will be shorted.  This procedure isderived directly from N-port admittance matrix theory.  The taskis to find the resulting current at each port (place of antennaattachment).     FIGURE 5 illustrates the concept for an N element antennaexcited at port 4.  Only a few of the ports are shown.  Thedistance between ports is given by the variable DZL.            PORT:  2        3        4        5                   ----------------------------------------------                   |        |        +        |                            |        |                 |                            |        |                 |                            |        |                 |                    o o o   |        |        V        |    o o o                    |        |                 |                            |        |                 |                            |        |                 |                            |        |        -        |                   ----------------------------------------------                   |<-DZL2->|<-DZL3->|<-DZL4->|                   FIGURE 5.  Transmission Line Equivalent Circuit     For the following discussion, please refer to any standardelectromagnetics text.  For example, see [2][3].  Also see[4][7][8].     It is obvious by inspection that given an excitation atelement 4, a current will flow only through the shorts at ports3, 4, and 5.  Current will not flow at the other ports.  Thecurrent at port 4 is the current through the source, V.  Thetransmission line equation tells us that the impedance seen byport 4 in the direction of port 3 is equal to     Z43 = j ZO tan(Beta * DZL3)where ZO is the characteristic impedance of the line, and Betais the wavenumber.  The admittance (Y) is one over the impedanceso,     Y43 = -j YO cot(Beta * DZL3)where YO = 1/ZO.  Similarly, the admittance seen by port 4 inthe direction of port 5 is      Y45 = -j YO cot(Beta * DZL4)Therefore, the current flowing through port 4 (excited by a unitvoltage) is     Y43 + Y45 = I4 / 1     To find the current in port 3, the following generaltransmission line equation is used.     V(DZL3) = V3 * cos(Beta*ZL3) + j * I3'' * ZO * sin(Beta*ZL3)where V3 and I3'' are the voltage and current at port 3,respectively.  (Note:  the primes do not representdifferentiation.)  Since port 3 is shorted, V3 = 0. Furthermore, V(DZL3) is just the excitation voltage, V4 = 1 Volt.  Therefore,     1 = j * I3'' * ZO * sin(Beta*ZL3)or     I3'' / 1 = -j YO * csc(Beta*L)However, this definition of I3'' is reversed from that of thestandard N-port definitions;  it flows out of the port insteadof in to it.  Therefore, we remove one prime ('') and change thesign.     I3' / 1 = j YO * csc(Beta*L)One step remains.  Since we arranged for a phase reversal bycrossing the wires in the transmission line [], we must accountfor this by changing the sign again.  The final form for thecurrent is then     I3 / 1 = -j YO * csc(Beta*L)The admittance seen in port 3 due to an excitation at port 4 isthen     Y34 = -j YO * csc(Beta*L)     Notice that the resulting matrix will be tri-diagonal. That is, it will have non-zero elements only along its majordiagonal and the diagonals on either side of it.     The termination impedance is accounted when the admittanceseen by element N is calculated.  The transmission line equationtells the equivalent impedance seen by element N in the directionof the load.     The program does not use the admittance matrix to account forthe source transmission line and source resistance.  Instead,it accounts for the effect of these items later after the solutionfor the antenna is obtained.     The resulting tri-diagonal admittance matrix is called YT inthe program.3.3.  COMBINING THE MATRICES     At this point we have one matrix, ZA, which describes howthe elements interact with each other.  Another matrix, YT,describes how the transmission line propagates energy.  We wishto combine the two.  Following [7], the connection of theN-port antenna elements network (ZA) and the N-port transmissionline network (YT) amounts to connecting the two N-ports inparallel.  Therefore we can write that     Iel = YA Vel     IT = YT VTwhere Iel is the current at the input to the antenna elements         (A column vector)      YA is the inverse of ZA         (A square matrix)      Vel is the voltage at the input to the antenna elements         (A column vector)      IT is the current at the ports of the transmission line         (A column vector)      VT is the voltage at the ports of the transmission line         (A column vector)Since the connection occurs in parallel, the total current isthen     I = Iel + ITHere, I represents the excitation current.  For a log-periodicdipole array, we excite the shortest element, element 1, only. Therefore, I = [1 0 0 ... 0]T (T denotes transpose).  Whenwe make the connection, Vel = VT.  Therefore,     I = (YA + YT) Vel(Here this text departs from [7].)  We want the voltages on eachantenna element measured at the port.  Therefore, we rewritethis equation as     (ZAZT) = inverse of (YA + YT)     Vel = (ZAZT) IFrom this,     Iel = YA Vel     The references [4][6][7] recast the equations slightly to makethem faster to evaluate.  For this program, the straightforwardapproach is fast enough.3.4.  FINDING THE INPUT AND TERMINATION CURRENTS     Now at last we have the antenna currents and voltages. Before we calculate the critical parameters, let us find thesource and termination currents and voltages.  For this theory,we again consult [2][3], and write     I(z') = IL * cos(Beta*z') + j * VL / ZO * sin(Beta*z')     V(z') = VL cos(Beta*z') + j * IL * ZO * sin(Beta*z')Here, z' is a distance measured from the load to the source      VL is the voltage at the load      IL is the current at the load      ZO is the characteristic impedance of the transmission lineTo find the source current and voltage, we reduce the antenna tothe source generator, Vin, and an equivalent impedance whichreplaces everything but the source and the input transmissionline (ZinA).  The result is a diagram similar to FIGURE 2 where the antenna becomes the load.  Therefore, we set       z'    = LLin (Length of source transmission line)     V(z') = Vin'     I(z') = Iin     VL    = Vel1     IL    = 1     ZO    = ZCin     Note that     ZinA = Vel1 / 1 Amp = Vel1     This is the input impedance measured at the shortest element ofthe dipole array.  The result of the above substitutions is      Iin  = cos(Beta*LLin) + j * Vel1 / ZO * sin(Beta*LLin)     Vin' = Vel1 * cos(Beta*LLin) + j * ZO * sin(Beta*LLin)These are explicit expressions for Iin and Vin'.  Vin' is thevoltage, not at the source, but after the current drop acrossthe source resistance is accounted as shown in Figure 6.                         Iin->          |--- Rs -------------| + Vin'          |   (source          |          |  resistance)    (ZinAS - antenna impedance     Vin  O                  as seen by the          |                  voltage source)          |                    |          |--------------------| -               FIGURE 6. Vin, Iin, and Vin'                                  Rs + ZinASTherefore, Vin = ---------- Vin'                   ZinASZinAS can be determined from the transmission line equationor by     ZinAS = Vin'/Iin     It is the antenna input impedance as seen by the source.The power accepted by the antenna is           1     Pin = - (Iin) (Iin*) [real(ZinAS) + Rs]           2where * indicates complex conjugate.     Note that confusion might exist about the definition ofthe input impedance.  There are two definitions:  ZinA is theinput impedance measured at the shortest element of theantenna array, and ZinAS is the input impedance as seen by thevoltage source.  Note that the magnitude of ZinAS will varywith the length of the input transmission line.  The reasonfor this is that for an antenna which is not precisely matchedto the characteristic impedance of the input transmission line,a standing wave exists on this line.  For this reason, a designengineer might be interested in both measures od input impedance.     Finding the termination current and voltage is similar.This time the antenna is the source and the termination is theload.  The above equations must be turned around to yield     Vout = VelN * cos(Beta*LLout) - j*IN'  * ZO*sin(Beta*LLout)     Iout = IN'  * cos(Beta*LLout) - j*VelN / ZO*sin(Beta*LLout)where      VelN is the voltage present at the terminals of the last         (longest) element      LLout is the length of the termination transmission line      ZO is the termination transmission line characteristic         impedance (equal to the antenna transmission line          characteristic impedance)and where     IN' = VelN / ZR                Zout + j * ZO   * tan(Beta * LLout)     ZR = ZO * -------------------------------------                 ZO   + j * Zout * tan(Beta * LLout)

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