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📄 ch4_2.java

📁 Java环境下实现的数值分析程序
💻 JAVA
字号:
class ch4_2{
	public static double EX(double x){
		double L=((x-0.42)*(x-0.50)*(x-0.58)*(x-0.66)*(x-0.72))*1.04403/((0.30-0.42)*(0.30-0.50)*(0.30-0.58)*(0.30-0.66)*(0.30-0.72))
		        +((x-0.30)*(x-0.50)*(x-0.58)*(x-0.66)*(x-0.72))*1.08462/((0.42-0.30)*(0.42-0.50)*(0.42-0.58)*(0.42-0.66)*(0.42-0.72))
		        +((x-0.30)*(x-0.42)*(x-0.58)*(x-0.66)*(x-0.72))*1.11803/((0.50-0.30)*(0.50-0.42)*(0.50-0.58)*(0.50-0.66)*(0.50-0.72))
		        +((x-0.30)*(x-0.42)*(x-0.50)*(x-0.66)*(x-0.72))*1.15603/((0.58-0.30)*(0.58-0.42)*(0.58-0.50)*(0.58-0.66)*(0.58-0.72))
	        	+((x-0.30)*(x-0.42)*(x-0.50)*(x-0.58)*(x-0.72))*1.19817/((0.66-0.30)*(0.66-0.42)*(0.66-0.50)*(0.66-0.58)*(0.66-0.72))
		        +((x-0.30)*(x-0.42)*(x-0.50)*(x-0.58)*(x-0.66))*1.23223/((0.72-0.30)*(0.72-0.42)*(0.72-0.50)*(0.72-0.58)*(0.72-0.66));
		return L;
	}
	
	public static void main(String[]args){
		System.out.println("L(0.46)="+EX(0.46));
		System.out.println("L(0.55)="+EX(0.55));
		System.out.println("L(0.60)="+EX(0.60));
	}
}

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