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📄 div_xsig.s

📁 linux 内核源代码
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	.file	"div_Xsig.S"/*---------------------------------------------------------------------------+ |  div_Xsig.S                                                               | |                                                                           | | Division subroutine for 96 bit quantities                                 | |                                                                           | | Copyright (C) 1994,1995                                                   | |                       W. Metzenthen, 22 Parker St, Ormond, Vic 3163,      | |                       Australia.  E-mail billm@jacobi.maths.monash.edu.au | |                                                                           | |                                                                           | +---------------------------------------------------------------------------*//*---------------------------------------------------------------------------+ | Divide the 96 bit quantity pointed to by a, by that pointed to by b, and  | | put the 96 bit result at the location d.                                  | |                                                                           | | The result may not be accurate to 96 bits. It is intended for use where   | | a result better than 64 bits is required. The result should usually be    | | good to at least 94 bits.                                                 | | The returned result is actually divided by one half. This is done to      | | prevent overflow.                                                         | |                                                                           | |  .aaaaaaaaaaaaaa / .bbbbbbbbbbbbb  ->  .dddddddddddd                      | |                                                                           | |  void div_Xsig(Xsig *a, Xsig *b, Xsig *dest)                              | |                                                                           | +---------------------------------------------------------------------------*/#include "exception.h"#include "fpu_emu.h"#define	XsigLL(x)	(x)#define	XsigL(x)	4(x)#define	XsigH(x)	8(x)#ifndef NON_REENTRANT_FPU/*	Local storage on the stack:	Accumulator:	FPU_accum_3:FPU_accum_2:FPU_accum_1:FPU_accum_0 */#define FPU_accum_3	-4(%ebp)#define FPU_accum_2	-8(%ebp)#define FPU_accum_1	-12(%ebp)#define FPU_accum_0	-16(%ebp)#define FPU_result_3	-20(%ebp)#define FPU_result_2	-24(%ebp)#define FPU_result_1	-28(%ebp)#else.data/*	Local storage in a static area:	Accumulator:	FPU_accum_3:FPU_accum_2:FPU_accum_1:FPU_accum_0 */	.align 4,0FPU_accum_3:	.long	0FPU_accum_2:	.long	0FPU_accum_1:	.long	0FPU_accum_0:	.long	0FPU_result_3:	.long	0FPU_result_2:	.long	0FPU_result_1:	.long	0#endif /* NON_REENTRANT_FPU */.textENTRY(div_Xsig)	pushl	%ebp	movl	%esp,%ebp#ifndef NON_REENTRANT_FPU	subl	$28,%esp#endif /* NON_REENTRANT_FPU */ 	pushl	%esi	pushl	%edi	pushl	%ebx	movl	PARAM1,%esi	/* pointer to num */	movl	PARAM2,%ebx	/* pointer to denom */#ifdef PARANOID	testl	$0x80000000, XsigH(%ebx)	/* Divisor */	je	L_bugged#endif /* PARANOID *//*---------------------------------------------------------------------------+ |  Divide:   Return  arg1/arg2 to arg3.                                     | |                                                                           | |  The maximum returned value is (ignoring exponents)                       | |               .ffffffff ffffffff                                          | |               ------------------  =  1.ffffffff fffffffe                  | |               .80000000 00000000                                          | | and the minimum is                                                        | |               .80000000 00000000                                          | |               ------------------  =  .80000000 00000001   (rounded)       | |               .ffffffff ffffffff                                          | |                                                                           | +---------------------------------------------------------------------------*/	/* Save extended dividend in local register */	/* Divide by 2 to prevent overflow */	clc	movl	XsigH(%esi),%eax	rcrl	%eax	movl	%eax,FPU_accum_3	movl	XsigL(%esi),%eax	rcrl	%eax	movl	%eax,FPU_accum_2	movl	XsigLL(%esi),%eax	rcrl	%eax	movl	%eax,FPU_accum_1	movl	$0,%eax	rcrl	%eax	movl	%eax,FPU_accum_0	movl	FPU_accum_2,%eax	/* Get the current num */	movl	FPU_accum_3,%edx/*----------------------------------------------------------------------*//* Initialization done.   Do the first 32 bits. */	/* We will divide by a number which is too large */	movl	XsigH(%ebx),%ecx	addl	$1,%ecx	jnc	LFirst_div_not_1	/* here we need to divide by 100000000h,	   i.e., no division at all.. */	mov	%edx,%eax	jmp	LFirst_div_doneLFirst_div_not_1:	divl	%ecx		/* Divide the numerator by the augmented				   denom ms dw */LFirst_div_done:	movl	%eax,FPU_result_3	/* Put the result in the answer */	mull	XsigH(%ebx)	/* mul by the ms dw of the denom */	subl	%eax,FPU_accum_2	/* Subtract from the num local reg */	sbbl	%edx,FPU_accum_3	movl	FPU_result_3,%eax	/* Get the result back */	mull	XsigL(%ebx)	/* now mul the ls dw of the denom */	subl	%eax,FPU_accum_1	/* Subtract from the num local reg */	sbbl	%edx,FPU_accum_2	sbbl	$0,FPU_accum_3	je	LDo_2nd_32_bits		/* Must check for non-zero result here */#ifdef PARANOID	jb	L_bugged_1#endif /* PARANOID */ 	/* need to subtract another once of the denom */	incl	FPU_result_3	/* Correct the answer */	movl	XsigL(%ebx),%eax	movl	XsigH(%ebx),%edx	subl	%eax,FPU_accum_1	/* Subtract from the num local reg */	sbbl	%edx,FPU_accum_2#ifdef PARANOID	sbbl	$0,FPU_accum_3	jne	L_bugged_1	/* Must check for non-zero result here */#endif /* PARANOID */ /*----------------------------------------------------------------------*//* Half of the main problem is done, there is just a reduced numerator   to handle now.   Work with the second 32 bits, FPU_accum_0 not used from now on */LDo_2nd_32_bits:	movl	FPU_accum_2,%edx	/* get the reduced num */	movl	FPU_accum_1,%eax	/* need to check for possible subsequent overflow */	cmpl	XsigH(%ebx),%edx	jb	LDo_2nd_div	ja	LPrevent_2nd_overflow	cmpl	XsigL(%ebx),%eax	jb	LDo_2nd_divLPrevent_2nd_overflow:/* The numerator is greater or equal, would cause overflow */	/* prevent overflow */	subl	XsigL(%ebx),%eax	sbbl	XsigH(%ebx),%edx	movl	%edx,FPU_accum_2	movl	%eax,FPU_accum_1	incl	FPU_result_3	/* Reflect the subtraction in the answer */#ifdef PARANOID	je	L_bugged_2	/* Can't bump the result to 1.0 */#endif /* PARANOID */ LDo_2nd_div:	cmpl	$0,%ecx		/* augmented denom msw */	jnz	LSecond_div_not_1	/* %ecx == 0, we are dividing by 1.0 */	mov	%edx,%eax	jmp	LSecond_div_doneLSecond_div_not_1:	divl	%ecx		/* Divide the numerator by the denom ms dw */LSecond_div_done:	movl	%eax,FPU_result_2	/* Put the result in the answer */	mull	XsigH(%ebx)	/* mul by the ms dw of the denom */	subl	%eax,FPU_accum_1	/* Subtract from the num local reg */	sbbl	%edx,FPU_accum_2#ifdef PARANOID	jc	L_bugged_2#endif /* PARANOID */	movl	FPU_result_2,%eax	/* Get the result back */	mull	XsigL(%ebx)	/* now mul the ls dw of the denom */	subl	%eax,FPU_accum_0	/* Subtract from the num local reg */	sbbl	%edx,FPU_accum_1	/* Subtract from the num local reg */	sbbl	$0,FPU_accum_2#ifdef PARANOID	jc	L_bugged_2#endif /* PARANOID */	jz	LDo_3rd_32_bits#ifdef PARANOID	cmpl	$1,FPU_accum_2	jne	L_bugged_2#endif /* PARANOID */ 	/* need to subtract another once of the denom */	movl	XsigL(%ebx),%eax	movl	XsigH(%ebx),%edx	subl	%eax,FPU_accum_0	/* Subtract from the num local reg */	sbbl	%edx,FPU_accum_1	sbbl	$0,FPU_accum_2#ifdef PARANOID	jc	L_bugged_2	jne	L_bugged_2#endif /* PARANOID */ 	addl	$1,FPU_result_2	/* Correct the answer */	adcl	$0,FPU_result_3#ifdef PARANOID	jc	L_bugged_2	/* Must check for non-zero result here */#endif /* PARANOID */ /*----------------------------------------------------------------------*//* The division is essentially finished here, we just need to perform   tidying operations.   Deal with the 3rd 32 bits */LDo_3rd_32_bits:	/* We use an approximation for the third 32 bits.	To take account of the 3rd 32 bits of the divisor	(call them del), we subtract  del * (a/b) */	movl	FPU_result_3,%eax	/* a/b */	mull	XsigLL(%ebx)		/* del */	subl	%edx,FPU_accum_1	/* A borrow indicates that the result is negative */	jnb	LTest_over	movl	XsigH(%ebx),%edx	addl	%edx,FPU_accum_1	subl	$1,FPU_result_2		/* Adjust the answer */	sbbl	$0,FPU_result_3	/* The above addition might not have been enough, check again. */	movl	FPU_accum_1,%edx	/* get the reduced num */	cmpl	XsigH(%ebx),%edx	/* denom */	jb	LDo_3rd_div	movl	XsigH(%ebx),%edx	addl	%edx,FPU_accum_1	subl	$1,FPU_result_2		/* Adjust the answer */	sbbl	$0,FPU_result_3	jmp	LDo_3rd_divLTest_over:	movl	FPU_accum_1,%edx	/* get the reduced num */	/* need to check for possible subsequent overflow */	cmpl	XsigH(%ebx),%edx	/* denom */	jb	LDo_3rd_div	/* prevent overflow */	subl	XsigH(%ebx),%edx	movl	%edx,FPU_accum_1	addl	$1,FPU_result_2	/* Reflect the subtraction in the answer */	adcl	$0,FPU_result_3LDo_3rd_div:	movl	FPU_accum_0,%eax	movl	FPU_accum_1,%edx	divl	XsigH(%ebx)	movl    %eax,FPU_result_1       /* Rough estimate of third word */	movl	PARAM3,%esi		/* pointer to answer */	movl	FPU_result_1,%eax	movl	%eax,XsigLL(%esi)	movl	FPU_result_2,%eax	movl	%eax,XsigL(%esi)	movl	FPU_result_3,%eax	movl	%eax,XsigH(%esi)L_exit:	popl	%ebx	popl	%edi	popl	%esi	leave	ret#ifdef PARANOID/* The logic is wrong if we got here */L_bugged:	pushl	EX_INTERNAL|0x240	call	EXCEPTION	pop	%ebx	jmp	L_exitL_bugged_1:	pushl	EX_INTERNAL|0x241	call	EXCEPTION	pop	%ebx	jmp	L_exitL_bugged_2:	pushl	EX_INTERNAL|0x242	call	EXCEPTION	pop	%ebx	jmp	L_exit#endif /* PARANOID */ 

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