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                              class=zi>点击“保存设置”按扭可使您本次阅读的整体设置(文字、字号、背景)得以保留,下次阅读时您就不必再重新设置,以符合您的阅读习惯。</TD></TR></TBODY></TABLE></TD></TR></TBODY></TABLE></DIV>
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                              color=#ffffff>.:.:经典c程序100例==21--30:.:.</FONT></B></TD>
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                              size=2>&nbsp;&nbsp;人气指数:<FONT 
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                              <P><FONT color=#ff9933><B><FONT size=5>    <FONT 
                              color=#3300cc>经典c程序100例==21--30</FONT></FONT></B></FONT></P>
                              <P><FONT 
                              color=#990000>【程序21】</FONT><BR>题目:猴子吃桃问题:猴子第一天摘下若干个桃子,当即吃了一半,还不瘾,又多吃了一个<BR>   第二天早上又将剩下的桃子吃掉一半,又多吃了一个。以后每天早上都吃了前一天剩下<BR>   的一半零一个。到第10天早上想再吃时,见只剩下一个桃子了。求第一天共摘了多少。<BR>1.程序分析:采取逆向思维的方法,从后往前推断。<BR>2.程序源代码:<BR>main()<BR>{<BR>int 
                              day,x1,x2;<BR>day=9;<BR>x2=1;<BR>while(day&gt;0)<BR> {x1=(x2+1)*2;/*第一天的桃子数是第2天桃子数加1后的2倍*/<BR> x2=x1;<BR> day--;<BR> }<BR>printf("the 
                              total is 
                              %d\n",x1);<BR>}<BR>==============================================================<BR><FONT 
                              color=#990000>【程序22】</FONT><BR>题目:两个乒乓球队进行比赛,各出三人。甲队为a,b,c三人,乙队为x,y,z三人。已抽签决定<BR>   比赛名单。有人向队员打听比赛的名单。a说他不和x比,c说他不和x,z比,请编程序找出<BR>   三队赛手的名单。 
                              <BR>1.程序分析:判断素数的方法:用一个数分别去除2到sqrt(这个数),如果能被整除,<BR>      则表明此数不是素数,反之是素数。 
                                    <BR>2.程序源代码:<BR>main()<BR>{<BR>char 
                              i,j,k;/*i是a的对手,j是b的对手,k是c的对手*/<BR>for(i='x';i&lt;='z';i++)<BR> for(j='x';j&lt;='z';j++)<BR> {<BR> if(i!=j)<BR>  for(k='x';k&lt;='z';k++)<BR>  { 
                              if(i!=k&amp;&amp;j!=k)<BR>   { 
                              if(i!='x'&amp;&amp;k!='x'&amp;&amp;k!='z')<BR>   printf("order 
                              is 
                              a--%c\tb--%c\tc--%c\n",i,j,k);<BR>   }<BR>  }<BR> }<BR>}<BR>==============================================================<BR><FONT 

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