📄 经典c程序100例==21--30.htm
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<P><FONT color=#ff9933><B><FONT size=5> <FONT
color=#3300cc>经典c程序100例==21--30</FONT></FONT></B></FONT></P>
<P><FONT
color=#990000>【程序21】</FONT><BR>题目:猴子吃桃问题:猴子第一天摘下若干个桃子,当即吃了一半,还不瘾,又多吃了一个<BR> 第二天早上又将剩下的桃子吃掉一半,又多吃了一个。以后每天早上都吃了前一天剩下<BR> 的一半零一个。到第10天早上想再吃时,见只剩下一个桃子了。求第一天共摘了多少。<BR>1.程序分析:采取逆向思维的方法,从后往前推断。<BR>2.程序源代码:<BR>main()<BR>{<BR>int
day,x1,x2;<BR>day=9;<BR>x2=1;<BR>while(day>0)<BR> {x1=(x2+1)*2;/*第一天的桃子数是第2天桃子数加1后的2倍*/<BR> x2=x1;<BR> day--;<BR> }<BR>printf("the
total is
%d\n",x1);<BR>}<BR>==============================================================<BR><FONT
color=#990000>【程序22】</FONT><BR>题目:两个乒乓球队进行比赛,各出三人。甲队为a,b,c三人,乙队为x,y,z三人。已抽签决定<BR> 比赛名单。有人向队员打听比赛的名单。a说他不和x比,c说他不和x,z比,请编程序找出<BR> 三队赛手的名单。
<BR>1.程序分析:判断素数的方法:用一个数分别去除2到sqrt(这个数),如果能被整除,<BR> 则表明此数不是素数,反之是素数。
<BR>2.程序源代码:<BR>main()<BR>{<BR>char
i,j,k;/*i是a的对手,j是b的对手,k是c的对手*/<BR>for(i='x';i<='z';i++)<BR> for(j='x';j<='z';j++)<BR> {<BR> if(i!=j)<BR> for(k='x';k<='z';k++)<BR> {
if(i!=k&&j!=k)<BR> {
if(i!='x'&&k!='x'&&k!='z')<BR> printf("order
is
a--%c\tb--%c\tc--%c\n",i,j,k);<BR> }<BR> }<BR> }<BR>}<BR>==============================================================<BR><FONT
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