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📄 螺旋方阵--fevernova的博客.htm

📁 螺旋矩阵的相关实验代码及报告 , 有相关的资料也有以最简单的方式直观实现的代码 .
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style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp;</SPAN>32<SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN>11
<P></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 132pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 11.0; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体">20<SPAN 
style="mso-spacerun: yes">&nbsp; </SPAN></SPAN><B><I><SPAN lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体; mso-fareast-font-family: 黑体">37</SPAN></I></B><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp; </SPAN>36<SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN>35<SPAN style="mso-spacerun: yes">&nbsp; </SPAN>34 </SPAN><B><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体; mso-fareast-font-family: 黑体"><SPAN 
style="mso-spacerun: yes">&nbsp;</SPAN><I>33</I></SPAN></B><SPAN lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp; </SPAN>12
<P></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 131.45pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 10.91; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><B><I><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体; mso-fareast-font-family: 黑体">19</SPAN></I></B><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp; </SPAN>18<SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN>17<SPAN style="mso-spacerun: yes">&nbsp; </SPAN>16<SPAN 
style="mso-spacerun: yes">&nbsp; </SPAN>15<SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN>14<SPAN style="mso-spacerun: yes">&nbsp; </SPAN></SPAN><B><I><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体; mso-fareast-font-family: 黑体">13</SPAN></I></B><I><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体">
<P></SPAN></I></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 30pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">为叙述方便我们称四个区域为上、下、左、右区。设<SPAN 
lang=EN-US>i、j为行列号,n为图形的总行数,则满足各区的范围是:
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 54pt; mso-char-indent-count: 4.5; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">上区:<SPAN 
lang=EN-US>j&gt;=i且j&lt;=n-i+1
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 54pt; mso-char-indent-count: 4.5; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">下区:<SPAN 
lang=EN-US>j&lt;=i且j&gt;=n-i+1
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 54pt; mso-char-indent-count: 4.5; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">左区:<SPAN 
lang=EN-US>j&lt;i且j&lt;n-i+1
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 54pt; mso-char-indent-count: 4.5; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">右区:<SPAN 
lang=EN-US>j&gt;i且j&gt;n-i+1
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 24pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 2.0; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">现在问题是,如果知道一行在不同区域开始第一个位置的数字,然后该区后续的数字就可利用前面分析的规律得到。<SPAN 
lang=EN-US>
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 24pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 2.0; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">对于右区开始各行第一个数字最易求出,为<SPAN 
lang=EN-US>4*(n-1)-i+1。后续一个和同行前一个数字之差是4*[n-1-(j-1)*2]+1,其中方括号内是每边的数字个数。
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 24pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 2.0; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">对角线上的数字是分区点,对角线上相临数字仍然相差一圈数字个数,读者自行分析得到计算公式。<SPAN 
lang=EN-US>
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 24pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 2.0; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">右区开始的第一个数字可以从上区结束时的数字按规律求出。<SPAN 
lang=EN-US>
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="TEXT-INDENT: 24pt; LINE-HEIGHT: 12pt; mso-char-indent-count: 2.0; mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt; mso-line-height-rule: exactly"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">下述程序用变量<SPAN 
lang=EN-US>s保存分区对角线上的数字。
<P></SPAN></SPAN></P>
<P class=MsoPlainText style="tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt">参考答案:<SPAN lang=EN-US>
<P></SPAN></SPAN></P>
<P class=MsoPlainText 
style="mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体">main( 
)
<P></SPAN></P>
<P class=MsoPlainText 
style="mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体">{<SPAN 
style="mso-spacerun: yes">&nbsp; </SPAN><SPAN 
style="mso-spacerun: yes">&nbsp;&nbsp;</SPAN>int i,j,k,n,s,m,t;
<P></SPAN></P>
<P class=MsoPlainText 
style="mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp;</SPAN><SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;</SPAN>printf("Please enter 
n:");
<P></SPAN></P>
<P class=MsoPlainText 
style="mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp;</SPAN><SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;</SPAN>scanf("%d",&amp;n);
<P></SPAN></P>
<P class=MsoPlainText 
style="mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 
style="mso-spacerun: yes">&nbsp;</SPAN><SPAN style="mso-spacerun: yes">&nbsp; 
</SPAN><SPAN style="mso-spacerun: yes">&nbsp;&nbsp;</SPAN>for (i=1;i&lt;=n;i++)
<P></SPAN></P>
<P class=MsoPlainText 
style="mso-char-indent-size: 12pt; tab-stops: 595.4pt 641.2pt 687.0pt 732.8pt"><SPAN 
lang=EN-US 
style="FONT-SIZE: 12pt; mso-bidi-font-size: 10.0pt; mso-hansi-font-family: 宋体"><SPAN 

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