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📄 testsmcomputer.cpp

📁 很好的矩阵链的计算代码
💻 CPP
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#include"Base.h"
#include"LSMatrix.h"
#include"RLSMatrix.h"

void main()
{
	int       n,flag=1,mu,nu,value;
	RLSMatrix in1,in2,out;

	
	
	printf("注意:以下矩阵的行数和列数均不超过20\n输入矩阵之前先输入矩阵的行数和列数\n");

	while(flag)
	{
		in1.mu=in1.nu=in1.tu=0;
		in2.mu=in2.nu=in2.tu=0;
		out.mu=out.nu=out.tu=0;
		printf("\n菜单:\n");
		printf("\n0.退出\n\n1.创建并输出矩阵\n\n2.求矩阵的逆\n\n3:求两矩阵的和\n\n4.求两矩阵减法\n\n5.求两矩阵乘积\n\n6.求矩阵的转置\n\n7.求矩阵行列式的值\n\n");
		printf("please choose from 0 ~7:\n");
		scanf("%d",&n);
		switch(n)
		{
			case 7: Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					printf("\n该矩阵的行列式的值为:%d\n",ValueSMatrix(in1));
					break;
			case 6:	Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					TransposeSMatrix(in1,out);
					PrintSMatrix(out);
					break;
			case 5: Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					printf("第二个矩阵:\n");
					Small(mu,nu);
					CreatSMatrix(in2,mu,nu);
					MulSMatrix(in1,in2,out);
					printf("\n两矩阵的乘积为:\n");
					PrintSMatrix(out);
					break;
			case 4:	printf("请输入第一个矩阵:\n");
					
					Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					printf("第二个矩阵:\n");
					Small(mu,nu);
					CreatSMatrix(in2,mu,nu);
					SubSMatrix(in1,in2,out);
					printf("\n两矩阵的差为:\n");
					PrintSMatrix(out);
					break;
			case 3:	printf("请输入第一个矩阵:\n");
					Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					printf("第二个矩阵:\n");
					Small(mu,nu);
					CreatSMatrix(in2,mu,nu);
					AddSMatrix(in1,in2,out);
					printf("\n两矩阵的和为:\n");
					PrintSMatrix(out);
					break;
			case 2:	printf("请输入矩阵:\n");
					Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					AthwartSMatrix(in1,out);
					printf("\n该矩阵的逆为:\n");
					PrintSMatrix(out);
				    break;
			case 1:	Small(mu,nu);
					CreatSMatrix(in1,mu,nu);
					printf("\n输出:\n");
					PrintSMatrix(in1);
					break;
			case 0: flag=0;break;
			default:printf("please input the right number\n");
		}
	}
}

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