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📄 shgeqz.f

📁 计算矩阵的经典开源库.全世界都在用它.相信你也不能例外.
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         RETURN      ELSE IF( LQUERY ) THEN         RETURN      END IF**     Quick return if possible*      IF( N.LE.0 ) THEN         WORK( 1 ) = REAL( 1 )*        --------------------- Begin Timing Code -----------------------         ITCNT = ZERO*        ---------------------- End Timing Code ------------------------         RETURN      END IF**     Initialize Q and Z*      IF( ICOMPQ.EQ.3 )     $   CALL SLASET( 'Full', N, N, ZERO, ONE, Q, LDQ )      IF( ICOMPZ.EQ.3 )     $   CALL SLASET( 'Full', N, N, ZERO, ONE, Z, LDZ )**     Machine Constants*      IN = IHI + 1 - ILO      SAFMIN = SLAMCH( 'S' )      SAFMAX = ONE / SAFMIN      ULP = SLAMCH( 'E' )*SLAMCH( 'B' )      ANORM = SLANHS( 'F', IN, A( ILO, ILO ), LDA, WORK )      BNORM = SLANHS( 'F', IN, B( ILO, ILO ), LDB, WORK )      ATOL = MAX( SAFMIN, ULP*ANORM )      BTOL = MAX( SAFMIN, ULP*BNORM )      ASCALE = ONE / MAX( SAFMIN, ANORM )      BSCALE = ONE / MAX( SAFMIN, BNORM )**     Set Eigenvalues IHI+1:N*      DO 30 J = IHI + 1, N         IF( B( J, J ).LT.ZERO ) THEN            IF( ILSCHR ) THEN               DO 10 JR = 1, J                  A( JR, J ) = -A( JR, J )                  B( JR, J ) = -B( JR, J )   10          CONTINUE            ELSE               A( J, J ) = -A( J, J )               B( J, J ) = -B( J, J )            END IF            IF( ILZ ) THEN               DO 20 JR = 1, N                  Z( JR, J ) = -Z( JR, J )   20          CONTINUE            END IF         END IF         ALPHAR( J ) = A( J, J )         ALPHAI( J ) = ZERO         BETA( J ) = B( J, J )   30 CONTINUE**     ---------------------- Begin Timing Code -------------------------*     Count ops for norms, etc.      OPST = ZERO      OPS = OPS + REAL( 2*N**2+6*N )*     ----------------------- End Timing Code --------------------------***     If IHI < ILO, skip QZ steps*      IF( IHI.LT.ILO )     $   GO TO 380**     MAIN QZ ITERATION LOOP**     Initialize dynamic indices**     Eigenvalues ILAST+1:N have been found.*        Column operations modify rows IFRSTM:whatever.*        Row operations modify columns whatever:ILASTM.**     If only eigenvalues are being computed, then*        IFRSTM is the row of the last splitting row above row ILAST;*        this is always at least ILO.*     IITER counts iterations since the last eigenvalue was found,*        to tell when to use an extraordinary shift.*     MAXIT is the maximum number of QZ sweeps allowed.*      ILAST = IHI      IF( ILSCHR ) THEN         IFRSTM = 1         ILASTM = N      ELSE         IFRSTM = ILO         ILASTM = IHI      END IF      IITER = 0      ESHIFT = ZERO      MAXIT = 30*( IHI-ILO+1 )*      DO 360 JITER = 1, MAXIT**        Split the matrix if possible.**        Two tests:*           1: A(j,j-1)=0  or  j=ILO*           2: B(j,j)=0*         IF( ILAST.EQ.ILO ) THEN**           Special case: j=ILAST*            GO TO 80         ELSE            IF( ABS( A( ILAST, ILAST-1 ) ).LE.ATOL ) THEN               A( ILAST, ILAST-1 ) = ZERO               GO TO 80            END IF         END IF*         IF( ABS( B( ILAST, ILAST ) ).LE.BTOL ) THEN            B( ILAST, ILAST ) = ZERO            GO TO 70         END IF**        General case: j<ILAST*         DO 60 J = ILAST - 1, ILO, -1**           Test 1: for A(j,j-1)=0 or j=ILO*            IF( J.EQ.ILO ) THEN               ILAZRO = .TRUE.            ELSE               IF( ABS( A( J, J-1 ) ).LE.ATOL ) THEN                  A( J, J-1 ) = ZERO                  ILAZRO = .TRUE.               ELSE                  ILAZRO = .FALSE.               END IF            END IF**           Test 2: for B(j,j)=0*            IF( ABS( B( J, J ) ).LT.BTOL ) THEN               B( J, J ) = ZERO**              Test 1a: Check for 2 consecutive small subdiagonals in A*               ILAZR2 = .FALSE.               IF( .NOT.ILAZRO ) THEN                  TEMP = ABS( A( J, J-1 ) )                  TEMP2 = ABS( A( J, J ) )                  TEMPR = MAX( TEMP, TEMP2 )                  IF( TEMPR.LT.ONE .AND. TEMPR.NE.ZERO ) THEN                     TEMP = TEMP / TEMPR                     TEMP2 = TEMP2 / TEMPR                  END IF                  IF( TEMP*( ASCALE*ABS( A( J+1, J ) ) ).LE.TEMP2*     $                ( ASCALE*ATOL ) )ILAZR2 = .TRUE.               END IF**              If both tests pass (1 & 2), i.e., the leading diagonal*              element of B in the block is zero, split a 1x1 block off*              at the top. (I.e., at the J-th row/column) The leading*              diagonal element of the remainder can also be zero, so*              this may have to be done repeatedly.*               IF( ILAZRO .OR. ILAZR2 ) THEN                  DO 40 JCH = J, ILAST - 1                     TEMP = A( JCH, JCH )                     CALL SLARTG( TEMP, A( JCH+1, JCH ), C, S,     $                            A( JCH, JCH ) )                     A( JCH+1, JCH ) = ZERO                     CALL SROT( ILASTM-JCH, A( JCH, JCH+1 ), LDA,     $                          A( JCH+1, JCH+1 ), LDA, C, S )                     CALL SROT( ILASTM-JCH, B( JCH, JCH+1 ), LDB,     $                          B( JCH+1, JCH+1 ), LDB, C, S )                     IF( ILQ )     $                  CALL SROT( N, Q( 1, JCH ), 1, Q( 1, JCH+1 ), 1,     $                             C, S )                     IF( ILAZR2 )     $                  A( JCH, JCH-1 ) = A( JCH, JCH-1 )*C                     ILAZR2 = .FALSE.**                    --------------- Begin Timing Code -----------------                     OPST = OPST + REAL( 7+12*( ILASTM-JCH )+6*NQ )*                    ---------------- End Timing Code ------------------*                     IF( ABS( B( JCH+1, JCH+1 ) ).GE.BTOL ) THEN                        IF( JCH+1.GE.ILAST ) THEN                           GO TO 80                        ELSE                           IFIRST = JCH + 1                           GO TO 110                        END IF                     END IF                     B( JCH+1, JCH+1 ) = ZERO   40             CONTINUE                  GO TO 70               ELSE**                 Only test 2 passed -- chase the zero to B(ILAST,ILAST)*                 Then process as in the case B(ILAST,ILAST)=0*                  DO 50 JCH = J, ILAST - 1                     TEMP = B( JCH, JCH+1 )                     CALL SLARTG( TEMP, B( JCH+1, JCH+1 ), C, S,     $                            B( JCH, JCH+1 ) )                     B( JCH+1, JCH+1 ) = ZERO                     IF( JCH.LT.ILASTM-1 )     $                  CALL SROT( ILASTM-JCH-1, B( JCH, JCH+2 ), LDB,     $                             B( JCH+1, JCH+2 ), LDB, C, S )                     CALL SROT( ILASTM-JCH+2, A( JCH, JCH-1 ), LDA,     $                          A( JCH+1, JCH-1 ), LDA, C, S )                     IF( ILQ )     $                  CALL SROT( N, Q( 1, JCH ), 1, Q( 1, JCH+1 ), 1,     $                             C, S )                     TEMP = A( JCH+1, JCH )                     CALL SLARTG( TEMP, A( JCH+1, JCH-1 ), C, S,     $                            A( JCH+1, JCH ) )                     A( JCH+1, JCH-1 ) = ZERO                     CALL SROT( JCH+1-IFRSTM, A( IFRSTM, JCH ), 1,     $                          A( IFRSTM, JCH-1 ), 1, C, S )                     CALL SROT( JCH-IFRSTM, B( IFRSTM, JCH ), 1,     $                          B( IFRSTM, JCH-1 ), 1, C, S )                     IF( ILZ )     $                  CALL SROT( N, Z( 1, JCH ), 1, Z( 1, JCH-1 ), 1,     $                             C, S )   50             CONTINUE**                 ---------------- Begin Timing Code -------------------                  OPST = OPST + REAL( 26+12*( ILASTM-IFRSTM )+6*     $                   ( NQ+NZ ) )*REAL( ILAST-J )*                 ----------------- End Timing Code --------------------*                  GO TO 70               END IF            ELSE IF( ILAZRO ) THEN**              Only test 1 passed -- work on J:ILAST*               IFIRST = J               GO TO 110            END IF**           Neither test passed -- try next J*   60    CONTINUE**        (Drop-through is "impossible")*         INFO = N + 1         GO TO 420**        B(ILAST,ILAST)=0 -- clear A(ILAST,ILAST-1) to split off a*        1x1 block.*   70    CONTINUE         TEMP = A( ILAST, ILAST )         CALL SLARTG( TEMP, A( ILAST, ILAST-1 ), C, S,     $                A( ILAST, ILAST ) )         A( ILAST, ILAST-1 ) = ZERO         CALL SROT( ILAST-IFRSTM, A( IFRSTM, ILAST ), 1,     $              A( IFRSTM, ILAST-1 ), 1, C, S )         CALL SROT( ILAST-IFRSTM, B( IFRSTM, ILAST ), 1,     $              B( IFRSTM, ILAST-1 ), 1, C, S )         IF( ILZ )     $      CALL SROT( N, Z( 1, ILAST ), 1, Z( 1, ILAST-1 ), 1, C, S )**        --------------------- Begin Timing Code -----------------------         OPST = OPST + REAL( 7+12*( ILAST-IFRSTM )+6*NZ )*        ---------------------- End Timing Code ------------------------***        A(ILAST,ILAST-1)=0 -- Standardize B, set ALPHAR, ALPHAI,*                              and BETA*   80    CONTINUE         IF( B( ILAST, ILAST ).LT.ZERO ) THEN            IF( ILSCHR ) THEN               DO 90 J = IFRSTM, ILAST                  A( J, ILAST ) = -A( J, ILAST )                  B( J, ILAST ) = -B( J, ILAST )   90          CONTINUE            ELSE               A( ILAST, ILAST ) = -A( ILAST, ILAST )               B( ILAST, ILAST ) = -B( ILAST, ILAST )            END IF            IF( ILZ ) THEN               DO 100 J = 1, N                  Z( J, ILAST ) = -Z( J, ILAST )  100          CONTINUE            END IF         END IF         ALPHAR( ILAST ) = A( ILAST, ILAST )         ALPHAI( ILAST ) = ZERO         BETA( ILAST ) = B( ILAST, ILAST )**        Go to next block -- exit if finished.*         ILAST = ILAST - 1         IF( ILAST.LT.ILO )     $      GO TO 380**        Reset counters*         IITER = 0         ESHIFT = ZERO         IF( .NOT.ILSCHR ) THEN            ILASTM = ILAST            IF( IFRSTM.GT.ILAST )     $         IFRSTM = ILO         END IF         GO TO 350**        QZ step**        This iteration only involves rows/columns IFIRST:ILAST. We*        assume IFIRST < ILAST, and that the diagonal of B is non-zero.*  110    CONTINUE         IITER = IITER + 1         IF( .NOT.ILSCHR ) THEN            IFRSTM = IFIRST         END IF**        Compute single shifts.**        At this point, IFIRST < ILAST, and the diagonal elements of*        B(IFIRST:ILAST,IFIRST,ILAST) are larger than BTOL (in*        magnitude)*         IF( ( IITER / 10 )*10.EQ.IITER ) THEN**           Exceptional shift.  Chosen for no particularly good reason.

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