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OrdinaryDifferentialEquation
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numericalAnalysis.ode</FONT>
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类 OrdinaryDifferentialEquation</H2>
<PRE>
java.lang.Object
<IMG SRC="../../resources/inherit.gif" ALT="继承者 "><B>numericalAnalysis.ode.OrdinaryDifferentialEquation</B>
</PRE>
<HR>
<DL>
<DT><PRE>public class <B>OrdinaryDifferentialEquation</B><DT>extends java.lang.Object</DL>
</PRE>
<P>
常微分方程初值问题数值解法.对照书:数值分析第二版,史万明等编,北京理工大学出版社
<P>
<P>
<DL>
<DT><B>作者：</B></DT>
<DD>山</DD>
</DL>
<HR>
<P>
<!-- ======== CONSTRUCTOR SUMMARY ======== -->
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<B>构造方法摘要</B></FONT></TH>
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<TR BGCOLOR="white" CLASS="TableRowColor">
<TD><CODE><B><A HREF="../../numericalAnalysis/ode/OrdinaryDifferentialEquation.html#OrdinaryDifferentialEquation(numericalAnalysis.function.Function, double, double)">OrdinaryDifferentialEquation</A></B>(<A HREF="../../numericalAnalysis/function/Function.html" title="numericalAnalysis.function 中的接口">Function</A> function,
double x0,
double y0)</CODE>
<BR>
新建一个常微分方程初值问题:y'=f(x,y),x属于某区间,y(x0)=y0.</TD>
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</TABLE>
<!-- ========== METHOD SUMMARY =========== -->
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<B>方法摘要</B></FONT></TH>
</TR>
<TR BGCOLOR="white" CLASS="TableRowColor">
<TD ALIGN="right" VALIGN="top" WIDTH="1%"><FONT SIZE="-1">
<CODE> java.lang.String</CODE></FONT></TD>
<TD><CODE><B><A HREF="../../numericalAnalysis/ode/OrdinaryDifferentialEquation.html#euler(double, double)">euler</A></B>(double h,
double xLimit)</CODE>
<BR>
欧拉公式</TD>
</TR>
<TR BGCOLOR="white" CLASS="TableRowColor">
<TD ALIGN="right" VALIGN="top" WIDTH="1%"><FONT SIZE="-1">
<CODE> java.lang.String</CODE></FONT></TD>
<TD><CODE><B><A HREF="../../numericalAnalysis/ode/OrdinaryDifferentialEquation.html#explicitAdams(double, double)">explicitAdams</A></B>(double h,
double xLimit)</CODE>
<BR>
显式四阶阿当姆斯公式(用龙格库塔法求表头y1,y,2,y3),求数值解</TD>
</TR>
<TR BGCOLOR="white" CLASS="TableRowColor">
<TD ALIGN="right" VALIGN="top" WIDTH="1%"><FONT SIZE="-1">
<CODE> double[][]</CODE></FONT></TD>
<TD><CODE><B><A HREF="../../numericalAnalysis/ode/OrdinaryDifferentialEquation.html#getSolution(double, double)">getSolution</A></B>(double h,
double xLimit)</CODE>
<BR>
求数值解xi,yi(i=0,1,...</TD>
</TR>
<TR BGCOLOR="white" CLASS="TableRowColor">
<TD ALIGN="right" VALIGN="top" WIDTH="1%"><FONT SIZE="-1">
<CODE> java.lang.String</CODE></FONT></TD>
<TD><CODE><B><A HREF="../../numericalAnalysis/ode/OrdinaryDifferentialEquation.html#predictorCorrectorAdams(double, double)">predictorCorrectorAdams</A></B>(double h,
double xLimit)</CODE>
<BR>
四阶阿当姆斯预测-校正法(用龙格库塔法求表头y1,y,2,y3),求数值解</TD>
</TR>
<TR BGCOLOR="white" CLASS="TableRowColor">
<TD ALIGN="right" VALIGN="top" WIDTH="1%"><FONT SIZE="-1">
<CODE> java.lang.String</CODE></FONT></TD>
<TD><CODE><B><A HREF="../../numericalAnalysis/ode/OrdinaryDifferentialEquation.html#rungeKutta(double, double)">rungeKutta</A></B>(double h,
double xLimit)</CODE>
<BR>
四阶古典龙格库塔法,求数值解</TD>
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<TD><CODE>equals, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait</CODE></TD>
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<B>构造方法详细信息</B></FONT></TH>
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<A NAME="OrdinaryDifferentialEquation(numericalAnalysis.function.Function, double, double)"><!-- --></A><H3>
OrdinaryDifferentialEquation</H3>
<PRE>
public <B>OrdinaryDifferentialEquation</B>(<A HREF="../../numericalAnalysis/function/Function.html" title="numericalAnalysis.function 中的接口">Function</A> function,
double x0,
double y0)</PRE>
<DL>
<DD>新建一个常微分方程初值问题:y'=f(x,y),x属于某区间,y(x0)=y0.
<P>
<DL>
<DT><B>参数：</B><DD><CODE>function</CODE> - y'=f(x,y)的f(x,y)函数实现的接口的对象<DD><CODE>x0</CODE> - 初始条件y(x0)=y0<DD><CODE>y0</CODE> - 初始条件y(x0)=y0</DL>
</DL>
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<B>方法详细信息</B></FONT></TH>
</TR>
</TABLE>
<A NAME="getSolution(double, double)"><!-- --></A><H3>
getSolution</H3>
<PRE>
public double[][] <B>getSolution</B>(double h,
double xLimit)</PRE>
<DL>
<DD>求数值解xi,yi(i=0,1,...,n)(用龙格库塔法)
<P>
<DD><DL>
<DT><B>参数：</B><DD><CODE>h</CODE> - 步长,则构造节点xi=x0+i*h<DD><CODE>xLimit</CODE> - 节点xi最大值(xi上限)
<DT><B>返回：</B><DD>一个二维数组,其第一维索引从0到n(n为节点个数减1),代表一个节点的xi和yi对; 第二维索引只有0,1,0表示xi,1表示yi.例如:若访问这个二维数组的[3][0]索引,则访问x3, 若访问这个二维数组的[3][1]索引,则访问y3</DL>
</DD>
</DL>
<HR>
<A NAME="euler(double, double)"><!-- --></A><H3>
euler</H3>
<PRE>
public java.lang.String <B>euler</B>(double h,
double xLimit)</PRE>
<DL>
<DD>欧拉公式
<P>
<DD><DL>
<DT><B>参数：</B><DD><CODE>h</CODE> - 步长,则构造节点xi=x0+i*h<DD><CODE>xLimit</CODE> - 节点xi最大值(xi上限)
<DT><B>返回：</B><DD>结果</DL>
</DD>
</DL>
<HR>
<A NAME="rungeKutta(double, double)"><!-- --></A><H3>
rungeKutta</H3>
<PRE>
public java.lang.String <B>rungeKutta</B>(double h,
double xLimit)</PRE>
<DL>
<DD>四阶古典龙格库塔法,求数值解
<P>
<DD><DL>
<DT><B>参数：</B><DD><CODE>h</CODE> - 步长,则构造节点xi=x0+i*h<DD><CODE>xLimit</CODE> - 节点xi最大值(xi上限)
<DT><B>返回：</B><DD>结果</DL>
</DD>
</DL>
<HR>
<A NAME="explicitAdams(double, double)"><!-- --></A><H3>
explicitAdams</H3>
<PRE>
public java.lang.String <B>explicitAdams</B>(double h,
double xLimit)</PRE>
<DL>
<DD>显式四阶阿当姆斯公式(用龙格库塔法求表头y1,y,2,y3),求数值解
<P>
<DD><DL>
<DT><B>参数：</B><DD><CODE>h</CODE> - 步长,则构造节点xi=x0+i*h<DD><CODE>xLimit</CODE> - 节点xi最大值(xi上限)
<DT><B>返回：</B><DD>结果</DL>
</DD>
</DL>
<HR>
<A NAME="predictorCorrectorAdams(double, double)"><!-- --></A><H3>
predictorCorrectorAdams</H3>
<PRE>
public java.lang.String <B>predictorCorrectorAdams</B>(double h,
double xLimit)</PRE>
<DL>
<DD>四阶阿当姆斯预测-校正法(用龙格库塔法求表头y1,y,2,y3),求数值解
<P>
<DD><DL>
<DT><B>参数：</B><DD><CODE>h</CODE> - 步长,则构造节点xi=x0+i*h<DD><CODE>xLimit</CODE> - 节点xi最大值(xi上限)
<DT><B>返回：</B><DD>结果</DL>
</DD>
</DL>
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