c11_015.c
来自「稀疏矩阵、链表、图、队列、二叉树、多叉树、排序、遗传算法等的实现」· C语言 代码 · 共 95 行
C
95 行
/* c11_015.c - demo of dynamically allocated 2D array
*
* C11_015 - dynamic allocation of arrays
*
* Copyright (C) 2000 Richard Heathfield
* Eton Computer Systems Ltd
* Macmillan Computer Publishing
*
* This program is free software; you can redistribute it
* and/or modify it under the terms of the GNU General
* Public License as published by the Free Software
* Foundation; either version 2 of the License, or
* (at your option) any later version.
*
* This program is distributed in the hope that it will
* be useful, but WITHOUT ANY WARRANTY; without even the
* implied warranty of MERCHANTABILITY or FITNESS FOR A
* PARTICULAR PURPOSE. See the GNU General Public License
* for more details.
*
* You should have received a copy of the GNU General
* Public License along with this program; if not, write
* to the Free Software Foundation, Inc., 675 Mass Ave,
* Cambridge, MA 02139, USA.
*
* Richard Heathfield may be contacted by email at:
* binary@eton.powernet.co.uk
*
*/
#include <stdio.h>
#include <stdlib.h>
#error This code invokes undefined behaviour. Please don't use it. See comment.
typedef int T;
T **Allocate(size_t m, size_t n)
{
int **a;
int *p;
size_t Row;
/* This method is not recommended in the chapter, but the chapter
* indicates that the code is at least portable. It isn't.
* This is because of possible differences in alignment requirements
* between T* and T**. I only realised this after the chapter had
* already been locked down, so I can't change the text, but at
* least I can put a friendly warning here.
*
* Well, you didn't really want to do it this way anyway, did you?
* :-)
*
* RJH 8 June 2000
*/
a = malloc(m * n * sizeof **a + m * sizeof *a);
if(a != NULL)
{
for(Row = 0, p = (T *)a + m; Row < m; Row++, p += n)
{
a[Row] = p;
}
}
return a;
}
int main(void)
{
T **array;
int i;
int j;
int total = 0;
int row = 4;
int col = 7;
array = Allocate(row, col);
if(array != NULL)
{
/* Populating the array */
for(i = 0; i < row; i++)
for(j = 0; j < col; j++)
array[i][j] = i + j;
/* Accessing the array */
for(i = 0; i < row; i++)
for(j = 0; j < col; j++)
total += array[i][j];
printf("Total is %d\n", total);
free(array);
}
return 0;
}
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