xiaotong.c

来自「C实现的MUD,对大家基本入门网络游戏很有帮助!」· C语言 代码 · 共 66 行

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// /NPC shinu.c#include <ansi.h>string ask_tea(object ob);inherit NPC;void create(){       set_name("绿衣小僮", ({ "luyi xiaotong", "xiaotong", "luyi"}));       set("long","他长得眉清目秀,是个专门侍茶的小僮。\n");       set("title","绝情谷侍童");       set("gender", "男性");       set("age", 15);       set("shen_type",1);       set("attitude", "peaceful");         set("str", 14);       set("int", 20);       set("con", 25);       set("dex", 20);       set("per", 20);       set("qi", 300);       set("max_qi", 300);       set("jing", 200);       set("max_jing", 200);       set("eff_jingli",200);       set("combat_exp",10000);       set("inquiry", ([		   "茶" : (: ask_tea :),       ]));       setup();       carry_object("/clone/misc/cloth")->wear();}void init(){               object ob;        ::init();        if( interactive(ob = this_player()) && !is_fighting() ) {                remove_call_out("greeting");                call_out("greeting", 1, ob);        }}void greeting(object ob){        if( !ob || environment(ob) != environment() ) return;        say("绿衣小僮笑吟吟地说道:这位" + RANK_D->query_respect(ob)             + "请了," + "我这就给您泡茶。\n");}string ask_tea(object ob){        object obj;       if ((this_player()->query("water")*10/this_player()->max_water_capacity())>8)            return "你怎么喝饱了还想要?";       if ( present("longjin cha", this_player()))            return "你先喝完了我给你的再说吧。";       if ( present("longjin cha",  environment(ob)) )            return "那不是有吗?先喝完了再说。";       obj=new("/d/jqg/obj/longjin");       obj->move(this_player());            return "这杯龙井茶给您,请慢点喝哟。";}

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