xisuijing.c

来自「C实现的MUD,对大家基本入门网络游戏很有帮助!」· C语言 代码 · 共 88 行

// xisuijing.c 洗髓经

inherit ITEM;
#include <ansi.h>
int do_study(string);
string* skill = ({
	"whip",
	"finger",
	"hand",
	"cuff",
	"claw",
	"strike",
});
void create()
{
        set_name(YEL"洗髓经"NOR, ({ "xisuijing" }));
        set_weight(100);
        if( clonep() )
                set_default_object(__FILE__);
        else
        {
                set("treasure",1);set("unit", "卷");
                set("long","这本破纸筒就是少林最高武学典籍，是达摩老祖面壁九年与易筋经一起
参悟出来的绝世典籍。\n");
                set("value", 10);
                set("material", "paper");
        }
}

void init()
{
	add_action("do_study","canwu");
}

int do_study(string arg)
{
	object where;
	object ob = this_object();
	object me = this_player();
	int myskill, cost, i, exp;

	cost=50;
	where = environment(me);
	if (!arg || !objectp(ob = present(arg, me)))
		return notify_fail("你要参悟什么？\n");
	if ((string)where->query("short")!="达摩院二楼")
		return notify_fail("洗髓经只能在达摩院里参悟！\n");
	if (!me->query_skill("literate",1)||me->query_skill("literate",1)<100)
	{
		write("你把纸筒翻来翻去，就是什么都读不懂。\n");
		return 1;
	}
//	if (!me->query_skill("yijinjing",1)||me->query_skill("yijinjing",1)<100)
//	{
//		write("也许是没有融会贯通易筋经，你觉得这洗髓经莫名其妙。\n");
//		return 1;
//	}
	if (me->is_busy())
		return notify_fail("你现在正忙着呢。\n");
	if (me->is_fighting() )
		return notify_fail("你无法在战斗中专心下来研读新知！\n");
	exp = (int)me->query("combat_exp");
	if (exp < 300000)
	{
		write("你的实战经验不足，不能参悟洗髓经。\n");
		return 1;
	}
	if ((int)me->query("jing")>cost)
	{
		for ( i=sizeof(skill); i>0; i-- )
		{
			myskill=me->query_skill(skill[i-1], 1);
			if ( myskill<180 && myskill>1 && myskill*myskill*myskill/10<exp)
			{
me->improve_skill(skill[i-1],(int)(me->query_skill("literate",1)+me->query("int"))/2);
			}
		}
		printf("你参悟洗髓经上的经文，似乎有点心得。\n");
		me->receive_damage("jing", cost );
	}
	else
	{
		cost=me->query("jing");
		write("你现在过于疲倦，无法专心下来参悟洗髓经。\n");
	}
	return 1;
}