who3.c

来自「C实现的MUD,对大家基本入门网络游戏很有帮助!」· C语言 代码 · 共 56 行

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// who3.cinherit F_CLEAN_UP;#include <ansi.h>int main(object me, string str){    object ob, *ob_list;    int i;    seteuid(getuid());    ob_list = users();    ob_list = sort_array(users(), "sort_user", this_object());    str = HIG" 玩家      悟性-后天 根骨-后天 身法-后天 膂力-后天 福缘 容貌\n"NOR;    str += "——————————————————————————————————\n";    for(i=0; i<sizeof(ob_list); i++)    {        ob = ob_list[i];        str += sprintf(NOR"%-10s  ",ob->name());        str += sprintf(HIR"%-2d:  ",ob->query("int"));        str += sprintf(HIR"%-2d   ",ob->query_int());        str += sprintf(HIG"%-2d:  ",ob->query("con"));        str += sprintf(HIG"%-2d   ",ob->query_con());        str += sprintf(HIY"%-2d:  ",ob->query("dex"));        str += sprintf(HIY"%-2d   ",ob->query_dex());        str += sprintf(HIB"%-2d:  ",ob->query("str"));        str += sprintf(HIB"%-2d   ",ob->query_str());        str += sprintf(HIC"%-2d   ",ob->query("kar"));        str += sprintf(HIM"%-2d \n"NOR, ob->query("per"));    }    str += "——————————————————————————————————\n";//    str = sprintf("%s共有 %d 位使用者连线中。\n", str, sizeof(ob_list));    me->start_more(str);    return 1;}int sort_user(object ob1, object ob2){        if( wizardp(ob1) && !wizardp(ob2) ) return -1;        if( wizardp(ob2) && !wizardp(ob1) ) return 1;        if( wizardp(ob1) && wizardp(ob2) )                return (int)SECURITY_D->get_wiz_level(ob2)                        - (int)SECURITY_D->get_wiz_level(ob1);        return (int)ob2->query("mud_age") - (int)ob1->query("mud_age");}int help(object me){        write(@HELP指令格式:who3玩家信息查询。HELP        );        return 1;}            

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