who3.c
来自「C实现的MUD,对大家基本入门网络游戏很有帮助!」· C语言 代码 · 共 56 行
C
56 行
// who3.cinherit F_CLEAN_UP;#include <ansi.h>int main(object me, string str){ object ob, *ob_list; int i; seteuid(getuid()); ob_list = users(); ob_list = sort_array(users(), "sort_user", this_object()); str = HIG" 玩家 悟性-后天 根骨-后天 身法-后天 膂力-后天 福缘 容貌\n"NOR; str += "——————————————————————————————————\n"; for(i=0; i<sizeof(ob_list); i++) { ob = ob_list[i]; str += sprintf(NOR"%-10s ",ob->name()); str += sprintf(HIR"%-2d: ",ob->query("int")); str += sprintf(HIR"%-2d ",ob->query_int()); str += sprintf(HIG"%-2d: ",ob->query("con")); str += sprintf(HIG"%-2d ",ob->query_con()); str += sprintf(HIY"%-2d: ",ob->query("dex")); str += sprintf(HIY"%-2d ",ob->query_dex()); str += sprintf(HIB"%-2d: ",ob->query("str")); str += sprintf(HIB"%-2d ",ob->query_str()); str += sprintf(HIC"%-2d ",ob->query("kar")); str += sprintf(HIM"%-2d \n"NOR, ob->query("per")); } str += "——————————————————————————————————\n";// str = sprintf("%s共有 %d 位使用者连线中。\n", str, sizeof(ob_list)); me->start_more(str); return 1;}int sort_user(object ob1, object ob2){ if( wizardp(ob1) && !wizardp(ob2) ) return -1; if( wizardp(ob2) && !wizardp(ob1) ) return 1; if( wizardp(ob1) && wizardp(ob2) ) return (int)SECURITY_D->get_wiz_level(ob2) - (int)SECURITY_D->get_wiz_level(ob1); return (int)ob2->query("mud_age") - (int)ob1->query("mud_age");}int help(object me){ write(@HELP指令格式:who3玩家信息查询。HELP ); return 1;}
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