call_out

来自「C实现的MUD,对大家基本入门网络游戏很有帮助!」· 代码 · 共 27 行

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          call_out() - delayed function call in same object

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          void call_out( string | function fun, int delay, mixed arg
          );

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          Set up a call of function <fun> in this_object(). The call
          will take place in <delay> seconds, with the argument <arg>
          provided. <arg> can be of any type.

          Please note that you can't rely on write() or say() in <fun>
          since this_player() is set to 0. Use tell_object() instead.

          The define THIS_PLAYER_IN_CALL_OUT exists to remedy the
          above problem.

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          remove_call_out(3), call_out_info(3)

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