wizardp
来自「C实现的MUD,对大家基本入门网络游戏很有帮助!」· 代码 · 共 19 行
TXT
19 行
wwwwiiiizzzzaaaarrrrddddpppp((((3333)))) MMMMuuuuddddOOOOSSSS ((((5555 SSSSeeeepppp 1111999999994444)))) wwwwiiiizzzzaaaarrrrddddpppp((((3333)))) NNNNAAAAMMMMEEEE wizardp() - determines if a given object had enable_wizard() performed in it SSSSYYYYNNNNOOOOPPPPSSSSIIIISSSS int wizardp( object ); DDDDEEEESSSSCCCCRRRRIIIIPPPPTTTTIIIIOOOONNNN Returns 1 if the arg had enable_wizard() performed on it. SSSSEEEEEEEE AAAALLLLSSSSOOOO disable_wizard(3), enable_wizard(3) Page 1 (printed 3/16/95)
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