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📄 yunu-sword.c

📁 C实现的MUD,对大家基本入门网络游戏很有帮助!
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// yunu-sword.c 玉女剑法// modified by Venus Oct.1997#include <ansi.h>inherit SKILL;mapping *action = ({    ([ "name":    "穿针引线",       "action":  "$N使一招「穿针引线」,脚踏中宫,手中$w直指$n$l",       "dodge":   50,       "damage":  170,       "damage_type":  "刺伤"    ]),    ([ "name":    "天衣无缝",       "action":  "$N剑随身转,一招「天衣无缝」,撒出一片剑影,罩向$n的$l",       "dodge":   30,       "damage":  80,       "damage_type":  "刺伤"    ]),    ([ "name":    "夜绣鸳鸯",       "action":  "$N舞动$w,使出一招「夜绣鸳鸯」剑光忽左忽右,闪烁不定,直刺$n的$l",       "dodge":   40,       "damage":  90,       "damage_type":  "刺伤"    ]),    ([ "name":    "织女穿梭",       "action":  "$N一声娇喝,祭出「织女穿梭」,手中$w化为一道弧光,射向$n的$l",       "dodge":   40,       "damage":  60,       "damage_type":  "刺伤"    ]),    ([ "name":    "小鸟依人",       "action":  "$N忽然蹂身直上,一招「小鸟依人」,手中$w自下往上刺向$n的$l",       "dodge":   50,       "damage":  90,       "damage_type":  "刺伤"    ]),});int valid_learn(object me){    object ob;   if( (string)me->query("gender") != "女性" )       return notify_fail("玉女金针十三剑是只有女子才能练的武功。\n");    if( (int)me->query("max_neili") < 50 )       return notify_fail("你的内力不够,没有办法练玉女金针十三剑。\n") ;   if( (string)me->query_skill_mapped("force")!= "zixia-shengong")       return notify_fail("玉女金针十三剑必须配合紫霞神功才能练。\n");   if( !(ob = me->query_temp("weapon"))       || (string)ob->query("skill_type") != "sword" )       return notify_fail("你必须先找一把剑才能练剑法。\n");    return 1;}int valid_enable(string usage){    return usage=="sword" || usage=="parry";}mapping query_action(object me, object weapon){    return action[random(sizeof(action))];}int practice_skill(object me){    if( (int)me->query("qi") < 30    ||  (int)me->query("neili") < 5 )      return notify_fail("你的内力或气不够,没有办法练习玉女金针十三剑。\n");    me->receive_damage("qi", 30);    me->add("neili", -5);    write("你按著所学练了一遍玉女金针十三剑。\n");    return 1;}int valid_effect(object me, object weapon, string name, int skill){}string perform_action_file(string action){        return __DIR__"yunu-sword/" + action;}

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