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📄 wenjia-quan.c

📁 C实现的MUD,对大家基本入门网络游戏很有帮助!
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// wenjia-quan 温家拳 (npc 功夫)inherit SKILL;mapping *action = ({([     "action" : "$N一式「兔戏苍鹰」,侧身挥拳,带着呼呼的风声打向$n的$l",       "force" : 180,        "dodge" : 20,        "parry" : 50,       "lvl" : 0,              "damage_type" : "内伤"]),([     "action" : "$N左拳虚握,右拳快如闪电般打向$n的$l,正是一招「飞流直泻」",       "force" : 205,        "dodge" : 20,       "lvl" : 0,        "damage_type" : "瘀伤"]),([     "action" : "$N使招「风雨归人」,双拳交错,忽又分开,引内劲打向$n的$l",       "force" : 340,        "dodge" : 10,        "parry" : 25,       "lvl" : 10,        "damage_type" : "内伤"]),([     "action" : "$N双拳犹如狂风骤雨般打向$n,拳影闪烁,已将$n团团围住",       "force" : 380,        "dodge" : 5,        "parry" : 30,       "lvl" : 10,        "damage_type" : "瘀伤"]),([     "action" : "$N纵身越起直落在$n身后,双脚落地后双拳向后挥出,打向$n的后心。",       "force" : 390,        "dodge" : 10,        "parry" : 35,       "lvl" : 30,        "damage_type" : "瘀伤"]),});int valid_enable(string usage) { return usage=="cuff" || usage=="parry"; }int valid_learn(object me){       if (me->query_temp("weapon") || me->query_temp("secondary_weapon"))               return notify_fail("温家拳拳必须空手。\n");             if ((int)me->query("max_neili") < 100)               return notify_fail("你的内力太弱,无法练功。\n");       return 1;}string query_skill_name(int level){        int i;        for(i = sizeof(action)-1; i >= 0; i--)                if(level >= action[i]["lvl"])                        return action[i]["skill_name"];}mapping query_action(object me, object weapon){        int i, level;       level   = (int) me->query_skill("wenjia-quan",1);        for(i = sizeof(action); i > 0; i--)                if(level > action[i-1]["lvl"])                        return action[NewRandom(i, 20, level/5)];}int practice_skill(object me){       if ((int)me->query("jingli") < 30)               return notify_fail("你的体力太低了。\n");       if ((int)me->query("neili") < 20)               return notify_fail("你的内力不够练温家拳。\n");       me->receive_damage("jingli", 30);       me->add("neili", -10);       return 1;}

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