calc.py
来自「M5,一个功能强大的多处理器系统模拟器.很多针对处理器架构,性能的研究都使用它作」· Python 代码 · 共 115 行
PY
115 行
# -----------------------------------------------------------------------------# calc.py## A simple calculator with variables. This is from O'Reilly's# "Lex and Yacc", p. 63.## This example uses unicode strings for tokens, docstrings, and input.# -----------------------------------------------------------------------------import syssys.path.insert(0,"../..")tokens = ( 'NAME','NUMBER', 'PLUS','MINUS','TIMES','DIVIDE','EQUALS', 'LPAREN','RPAREN', )# Tokenst_PLUS = ur'\+'t_MINUS = ur'-'t_TIMES = ur'\*'t_DIVIDE = ur'/'t_EQUALS = ur'='t_LPAREN = ur'\('t_RPAREN = ur'\)'t_NAME = ur'[a-zA-Z_][a-zA-Z0-9_]*'def t_NUMBER(t): ur'\d+' try: t.value = int(t.value) except ValueError: print "Integer value too large", t.value t.value = 0 return tt_ignore = u" \t"def t_newline(t): ur'\n+' t.lexer.lineno += t.value.count("\n")def t_error(t): print "Illegal character '%s'" % t.value[0] t.lexer.skip(1)# Build the lexerimport ply.lex as lexlex.lex()# Parsing rulesprecedence = ( ('left','PLUS','MINUS'), ('left','TIMES','DIVIDE'), ('right','UMINUS'), )# dictionary of namesnames = { }def p_statement_assign(p): 'statement : NAME EQUALS expression' names[p[1]] = p[3]def p_statement_expr(p): 'statement : expression' print p[1]def p_expression_binop(p): '''expression : expression PLUS expression | expression MINUS expression | expression TIMES expression | expression DIVIDE expression''' if p[2] == u'+' : p[0] = p[1] + p[3] elif p[2] == u'-': p[0] = p[1] - p[3] elif p[2] == u'*': p[0] = p[1] * p[3] elif p[2] == u'/': p[0] = p[1] / p[3]def p_expression_uminus(p): 'expression : MINUS expression %prec UMINUS' p[0] = -p[2]def p_expression_group(p): 'expression : LPAREN expression RPAREN' p[0] = p[2]def p_expression_number(p): 'expression : NUMBER' p[0] = p[1]def p_expression_name(p): 'expression : NAME' try: p[0] = names[p[1]] except LookupError: print "Undefined name '%s'" % p[1] p[0] = 0def p_error(p): print "Syntax error at '%s'" % p.valueimport ply.yacc as yaccyacc.yacc()while 1: try: s = raw_input('calc > ') except EOFError: break if not s: continue yacc.parse(unicode(s))
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?