main.cpp

杭电 ACM 1002 I have a very simple problem for you. Given two integers A and B, your job is to calcul

#include<iostream>
using namespace std;
int mian()
{
	int a, b, i, t;
	int num[100];
	while(cin >> t)
	{
		if(t < 1)
		{
			cout<< "Enter wrong" << endl;
		}
		else
		{
			for(i = 1; i <= t; i++)
			{
				cin >> a >> b;
				num[i * 2 - 2] = a;
				num[i * 2 - 1] = b;
			}
			for(i = 1; i <= t; i++)
			{
				cout << "case i: " << endl;
				cout << num[i * 2 - 2] << "+" << num[i * 2 - 1] << "=" << a + b << endl;
			}
		}
	} 
	return 0;
}