1201 18岁生日.cpp

来自「ACM 威士忌部分答案」· C++ 代码 · 共 48 行

/*
1201 18岁生日
Time Limit : 1000 ms  Memory Limit : 32768 K  Output Limit : 256 K

GUN C++
*/
#include<iostream>
#include<stdio.h>
using namespace std;

bool LeapYear(int year)
{
   if ((year%100!=0 && year%4==0) || (year%400==0)) return true;
   return false;
}

void run()
{
   int year, month, day;
   scanf("%d-%d-%d", &year, &month, &day);

   if(month==2 && day==29 && !LeapYear(year+18)){
       cout<<"-1"<<endl;
   }
   else{
       int count=0;   // 统计期间经过的闰年数
       if (!(month<=2 && day<=28))
           year++;

       for(int i=year; i<year+18; i++){
           if(LeapYear(i))    count++;
       }

       int days=18*365+count;
       cout<<days<<endl;
   }
}

int main()
{
   int total;
   cin>>total;
   for(int now=1; now<=total; now++) run();

   return 0;
}