channelcorrelationcoefficient.m

本人详细分析后的mimo信道容量的仿真代码

%% MIMO_ChannelCorrelationCoefficien
clear;
clc;
results=zeros(5,501);

%扩展角为30°
temp=15/180*pi;
results(1,:)=quadv(@CorrCoe,-temp,temp)/(30/180*pi);%求得的应该是相邻天线相关系数随天线间隔/波长的关系
%扩展角为20°时，求得的相邻天线相关系数随天线间隔/波长的关系
temp=10/180*pi;%转化为弧度，并取一半
results(2,:)=quadv(@CorrCoe,-temp,temp)/(20/180*pi);
%扩展角为10°
temp=5/180*pi;
results(3,:)=quadv(@CorrCoe,-temp,temp)/(10/180*pi);
%扩展角为5°
temp=2.5/180*pi;
results(4,:)=quadv(@CorrCoe,-temp,temp)/(5/180*pi);
%扩展角为1°
temp=0.5/180*pi;
results(5,:)=quadv(@CorrCoe,-temp,temp)/(1/180*pi);
%运行后的图形表示的是
d2lamda=0:0.1:50;
newresults=real(results).';
plot (d2lamda,newresults, 'DisplayName','newresults', 'YDataSource', 'newresults'); figure(gcf)
axis([0 50 -0.4 1])
grid

%C = log2(eye(4)+100/4*Re_CorrMatrix'*H*Tr_CorrMatrix*H');