lind6-5.c

谭浩强第二版的课后习题的答案的源程序

#include<stdio.h>
void main()
{
	double k,s=0;
	for(k=1;k<=100;k++)
	{
		s+=k;
	}
	for(k=1;k<=50;k++)
	{
		s+=k*k;
	}
	for(k=1;k<=10;k++)
	{
		s+=1/k;
	}
	printf("\n%.2lf\n",s);     //The result is 47977.93

}