lind5-8t.c

谭浩强第二版的课后习题的答案的源程序

#include<stdio.h>
main()
	{
	double dividend,i,t;
	int grade=1;              //dividend means "hong li, ti cheng",i represent benifet
	printf("\nPlease input the benefit.\n");
	scanf("%lf",&i);
	t=i;
	i=i-((long)i%100000);
	grade+=(long)i/1e5;
	if(grade>0)
	{
	switch(grade)
	{
	case 1:
	dividend=t*0.1;break;
	case 2:
	dividend=1e4+(t-1e5)*.075;break;
	case 3:
	case 4:
	dividend=1e4+1e5*.075+(t-2e5)*.05;break;
	case 5:
	case 6:
	dividend=1e4+1e5*.075+2e5*.05+(t-4e5)*.03;break;
	case 7:
	case 8:
	case 9:
	case 10:
	dividend=1e4+1e5*.075+2e5*.05+2e5*.03+(t-6e5)*.015;break;
	}
	printf("The dididend is %.2fyuan.\n",dividend);
	}
	else if(grade>10)      //change "if" to "else if", why it will run the "else"
	{
	dividend=1e4+1e5*.075+2e5*.05+2e5*.03+4e5*.015+(t-1e6)*.01;
	printf("The dididend is %.2fyuan.\n",dividend);
	}
	else
	printf("It is a false date.\n");
	}