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     lsll	%d6,%d4     movel	%d5,%d7			| ...a copy of D5     lsll	%d6,%d5     negl	%d6     addil	#32,%d6     lsrl	%d6,%d7     orl	%d7,%d4			| ...(D3,D4,D5) normalized     movel	%d3,X(%a6)     movel	%d4,XFRAC(%a6)     movel	%d5,XFRAC+4(%a6)     negl	%d2     movel	%d2,ADJK(%a6)     fmovex	X(%a6),%fp0     moveml	(%a7)+,%d2-%d7		| ...restore registers     lea	X(%a6),%a0     bras	LOGBGN			| ...begin regular log(X)	.global	slognslogn:|--ENTRY POINT FOR LOG(X) FOR X FINITE, NON-ZERO, NOT NAN'S	fmovex		(%a0),%fp0	| ...LOAD INPUT	movel		#0x00000000,ADJK(%a6)LOGBGN:|--FPCR SAVED AND CLEARED, INPUT IS 2^(ADJK)*FP0, FP0 CONTAINS|--A FINITE, NON-ZERO, NORMALIZED NUMBER.	movel	(%a0),%d0	movew	4(%a0),%d0	movel	(%a0),X(%a6)	movel	4(%a0),X+4(%a6)	movel	8(%a0),X+8(%a6)	cmpil	#0,%d0		| ...CHECK IF X IS NEGATIVE	blt	LOGNEG		| ...LOG OF NEGATIVE ARGUMENT IS INVALID	cmp2l	BOUNDS1,%d0	| ...X IS POSITIVE, CHECK IF X IS NEAR 1	bcc	LOGNEAR1	| ...BOUNDS IS ROUGHLY [15/16, 17/16]LOGMAIN:|--THIS SHOULD BE THE USUAL CASE, X NOT VERY CLOSE TO 1|--X = 2^(K) * Y, 1 <= Y < 2. THUS, Y = 1.XXXXXXXX....XX IN BINARY.|--WE DEFINE F = 1.XXXXXX1, I.E. FIRST 7 BITS OF Y AND ATTACH A 1.|--THE IDEA IS THAT LOG(X) = K*LOG2 + LOG(Y)|--			 = K*LOG2 + LOG(F) + LOG(1 + (Y-F)/F).|--NOTE THAT U = (Y-F)/F IS VERY SMALL AND THUS APPROXIMATING|--LOG(1+U) CAN BE VERY EFFICIENT.|--ALSO NOTE THAT THE VALUE 1/F IS STORED IN A TABLE SO THAT NO|--DIVISION IS NEEDED TO CALCULATE (Y-F)/F. |--GET K, Y, F, AND ADDRESS OF 1/F.	asrl	#8,%d0	asrl	#8,%d0		| ...SHIFTED 16 BITS, BIASED EXPO. OF X	subil	#0x3FFF,%d0 	| ...THIS IS K	addl	ADJK(%a6),%d0	| ...ADJUST K, ORIGINAL INPUT MAY BE  DENORM.	lea	LOGTBL,%a0 	| ...BASE ADDRESS OF 1/F AND LOG(F)	fmovel	%d0,%fp1		| ...CONVERT K TO FLOATING-POINT FORMAT|--WHILE THE CONVERSION IS GOING ON, WE GET F AND ADDRESS OF 1/F	movel	#0x3FFF0000,X(%a6)	| ...X IS NOW Y, I.E. 2^(-K)*X	movel	XFRAC(%a6),FFRAC(%a6)	andil	#0xFE000000,FFRAC(%a6) | ...FIRST 7 BITS OF Y	oril	#0x01000000,FFRAC(%a6) | ...GET F: ATTACH A 1 AT THE EIGHTH BIT	movel	FFRAC(%a6),%d0	| ...READY TO GET ADDRESS OF 1/F	andil	#0x7E000000,%d0		asrl	#8,%d0	asrl	#8,%d0	asrl	#4,%d0		| ...SHIFTED 20, D0 IS THE DISPLACEMENT	addal	%d0,%a0		| ...A0 IS THE ADDRESS FOR 1/F	fmovex	X(%a6),%fp0	movel	#0x3fff0000,F(%a6)	clrl	F+8(%a6)	fsubx	F(%a6),%fp0		| ...Y-F	fmovemx %fp2-%fp2/%fp3,-(%sp)	| ...SAVE FP2 WHILE FP0 IS NOT READY|--SUMMARY: FP0 IS Y-F, A0 IS ADDRESS OF 1/F, FP1 IS K|--REGISTERS SAVED: FPCR, FP1, FP2LP1CONT1:|--AN RE-ENTRY POINT FOR LOGNP1	fmulx	(%a0),%fp0	| ...FP0 IS U = (Y-F)/F	fmulx	LOGOF2,%fp1	| ...GET K*LOG2 WHILE FP0 IS NOT READY	fmovex	%fp0,%fp2	fmulx	%fp2,%fp2		| ...FP2 IS V=U*U	fmovex	%fp1,KLOG2(%a6)	| ...PUT K*LOG2 IN MEMORY, FREE FP1|--LOG(1+U) IS APPROXIMATED BY|--U + V*(A1+U*(A2+U*(A3+U*(A4+U*(A5+U*A6))))) WHICH IS|--[U + V*(A1+V*(A3+V*A5))]  +  [U*V*(A2+V*(A4+V*A6))]	fmovex	%fp2,%fp3	fmovex	%fp2,%fp1		fmuld	LOGA6,%fp1	| ...V*A6	fmuld	LOGA5,%fp2	| ...V*A5	faddd	LOGA4,%fp1	| ...A4+V*A6	faddd	LOGA3,%fp2	| ...A3+V*A5	fmulx	%fp3,%fp1		| ...V*(A4+V*A6)	fmulx	%fp3,%fp2		| ...V*(A3+V*A5)	faddd	LOGA2,%fp1	| ...A2+V*(A4+V*A6)	faddd	LOGA1,%fp2	| ...A1+V*(A3+V*A5)	fmulx	%fp3,%fp1		| ...V*(A2+V*(A4+V*A6))	addal	#16,%a0		| ...ADDRESS OF LOG(F)	fmulx	%fp3,%fp2		| ...V*(A1+V*(A3+V*A5)), FP3 RELEASED	fmulx	%fp0,%fp1		| ...U*V*(A2+V*(A4+V*A6))	faddx	%fp2,%fp0		| ...U+V*(A1+V*(A3+V*A5)), FP2 RELEASED	faddx	(%a0),%fp1	| ...LOG(F)+U*V*(A2+V*(A4+V*A6))	fmovemx  (%sp)+,%fp2-%fp2/%fp3	| ...RESTORE FP2	faddx	%fp1,%fp0		| ...FP0 IS LOG(F) + LOG(1+U)	fmovel	%d1,%fpcr	faddx	KLOG2(%a6),%fp0	| ...FINAL ADD	bra	t_frcinxLOGNEAR1:|--REGISTERS SAVED: FPCR, FP1. FP0 CONTAINS THE INPUT.	fmovex	%fp0,%fp1	fsubs	one,%fp1		| ...FP1 IS X-1	fadds	one,%fp0		| ...FP0 IS X+1	faddx	%fp1,%fp1		| ...FP1 IS 2(X-1)|--LOG(X) = LOG(1+U/2)-LOG(1-U/2) WHICH IS AN ODD POLYNOMIAL|--IN U, U = 2(X-1)/(X+1) = FP1/FP0LP1CONT2:|--THIS IS AN RE-ENTRY POINT FOR LOGNP1	fdivx	%fp0,%fp1		| ...FP1 IS U	fmovemx %fp2-%fp2/%fp3,-(%sp)	 | ...SAVE FP2|--REGISTERS SAVED ARE NOW FPCR,FP1,FP2,FP3|--LET V=U*U, W=V*V, CALCULATE|--U + U*V*(B1 + V*(B2 + V*(B3 + V*(B4 + V*B5)))) BY|--U + U*V*(  [B1 + W*(B3 + W*B5)]  +  [V*(B2 + W*B4)]  )	fmovex	%fp1,%fp0	fmulx	%fp0,%fp0	| ...FP0 IS V	fmovex	%fp1,SAVEU(%a6) | ...STORE U IN MEMORY, FREE FP1	fmovex	%fp0,%fp1		fmulx	%fp1,%fp1	| ...FP1 IS W	fmoved	LOGB5,%fp3	fmoved	LOGB4,%fp2	fmulx	%fp1,%fp3	| ...W*B5	fmulx	%fp1,%fp2	| ...W*B4	faddd	LOGB3,%fp3 | ...B3+W*B5	faddd	LOGB2,%fp2 | ...B2+W*B4	fmulx	%fp3,%fp1	| ...W*(B3+W*B5), FP3 RELEASED	fmulx	%fp0,%fp2	| ...V*(B2+W*B4)	faddd	LOGB1,%fp1 | ...B1+W*(B3+W*B5)	fmulx	SAVEU(%a6),%fp0 | ...FP0 IS U*V	faddx	%fp2,%fp1	| ...B1+W*(B3+W*B5) + V*(B2+W*B4), FP2 RELEASED	fmovemx (%sp)+,%fp2-%fp2/%fp3 | ...FP2 RESTORED	fmulx	%fp1,%fp0	| ...U*V*( [B1+W*(B3+W*B5)] + [V*(B2+W*B4)] )	fmovel	%d1,%fpcr	faddx	SAVEU(%a6),%fp0			bra	t_frcinx	rtsLOGNEG:|--REGISTERS SAVED FPCR. LOG(-VE) IS INVALID	bra	t_operr	.global	slognp1dslognp1d:|--ENTRY POINT FOR LOG(1+Z) FOR DENORMALIZED INPUT| Simply return the denorm	bra	t_extdnrm	.global	slognp1slognp1:|--ENTRY POINT FOR LOG(1+X) FOR X FINITE, NON-ZERO, NOT NAN'S	fmovex	(%a0),%fp0	| ...LOAD INPUT	fabsx	%fp0		|test magnitude	fcmpx	LTHOLD,%fp0	|compare with min threshold	fbgt	LP1REAL		|if greater, continue	fmovel	#0,%fpsr		|clr N flag from compare	fmovel	%d1,%fpcr	fmovex	(%a0),%fp0	|return signed argument	bra	t_frcinxLP1REAL:	fmovex	(%a0),%fp0	| ...LOAD INPUT	movel	#0x00000000,ADJK(%a6)	fmovex	%fp0,%fp1	| ...FP1 IS INPUT Z	fadds	one,%fp0	| ...X := ROUND(1+Z)	fmovex	%fp0,X(%a6)	movew	XFRAC(%a6),XDCARE(%a6)	movel	X(%a6),%d0	cmpil	#0,%d0	ble	LP1NEG0	| ...LOG OF ZERO OR -VE	cmp2l	BOUNDS2,%d0	bcs	LOGMAIN	| ...BOUNDS2 IS [1/2,3/2]|--IF 1+Z > 3/2 OR 1+Z < 1/2, THEN X, WHICH IS ROUNDING 1+Z,|--CONTAINS AT LEAST 63 BITS OF INFORMATION OF Z. IN THAT CASE,|--SIMPLY INVOKE LOG(X) FOR LOG(1+Z).LP1NEAR1:|--NEXT SEE IF EXP(-1/16) < X < EXP(1/16)	cmp2l	BOUNDS1,%d0	bcss	LP1CARELP1ONE16:|--EXP(-1/16) < X < EXP(1/16). LOG(1+Z) = LOG(1+U/2) - LOG(1-U/2)|--WHERE U = 2Z/(2+Z) = 2Z/(1+X).	faddx	%fp1,%fp1	| ...FP1 IS 2Z	fadds	one,%fp0	| ...FP0 IS 1+X|--U = FP1/FP0	bra	LP1CONT2LP1CARE:|--HERE WE USE THE USUAL TABLE DRIVEN APPROACH. CARE HAS TO BE|--TAKEN BECAUSE 1+Z CAN HAVE 67 BITS OF INFORMATION AND WE MUST|--PRESERVE ALL THE INFORMATION. BECAUSE 1+Z IS IN [1/2,3/2],|--THERE ARE ONLY TWO CASES.|--CASE 1: 1+Z < 1, THEN K = -1 AND Y-F = (2-F) + 2Z|--CASE 2: 1+Z > 1, THEN K = 0  AND Y-F = (1-F) + Z|--ON RETURNING TO LP1CONT1, WE MUST HAVE K IN FP1, ADDRESS OF|--(1/F) IN A0, Y-F IN FP0, AND FP2 SAVED.	movel	XFRAC(%a6),FFRAC(%a6)	andil	#0xFE000000,FFRAC(%a6)	oril	#0x01000000,FFRAC(%a6)	| ...F OBTAINED	cmpil	#0x3FFF8000,%d0	| ...SEE IF 1+Z > 1	bges	KISZEROKISNEG1:	fmoves	TWO,%fp0	movel	#0x3fff0000,F(%a6)	clrl	F+8(%a6)	fsubx	F(%a6),%fp0	| ...2-F	movel	FFRAC(%a6),%d0	andil	#0x7E000000,%d0	asrl	#8,%d0	asrl	#8,%d0	asrl	#4,%d0		| ...D0 CONTAINS DISPLACEMENT FOR 1/F	faddx	%fp1,%fp1		| ...GET 2Z	fmovemx %fp2-%fp2/%fp3,-(%sp)	| ...SAVE FP2 	faddx	%fp1,%fp0		| ...FP0 IS Y-F = (2-F)+2Z	lea	LOGTBL,%a0	| ...A0 IS ADDRESS OF 1/F	addal	%d0,%a0	fmoves	negone,%fp1	| ...FP1 IS K = -1	bra	LP1CONT1KISZERO:	fmoves	one,%fp0	movel	#0x3fff0000,F(%a6)	clrl	F+8(%a6)	fsubx	F(%a6),%fp0		| ...1-F	movel	FFRAC(%a6),%d0	andil	#0x7E000000,%d0	asrl	#8,%d0	asrl	#8,%d0	asrl	#4,%d0	faddx	%fp1,%fp0		| ...FP0 IS Y-F	fmovemx %fp2-%fp2/%fp3,-(%sp)	| ...FP2 SAVED	lea	LOGTBL,%a0	addal	%d0,%a0	 	| ...A0 IS ADDRESS OF 1/F	fmoves	zero,%fp1	| ...FP1 IS K = 0	bra	LP1CONT1LP1NEG0:|--FPCR SAVED. D0 IS X IN COMPACT FORM.	cmpil	#0,%d0	blts	LP1NEGLP1ZERO:	fmoves	negone,%fp0	fmovel	%d1,%fpcr	bra t_dzLP1NEG:	fmoves	zero,%fp0	fmovel	%d1,%fpcr	bra	t_operr	|end

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