crse.res

FOTURN编写的求临界转速的例子,相信对初学者很有帮助,里面有计算的参数

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   THE RESULTS OF CALCULATING THE CRITICAL ROTARY SPEED
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             ***** Nkp(      1)=   58946.2280273438     *****
 y(           0)=  -6.77267131566220     
 y(           1)=  -6.67267184011852     
 y(           2)=  -6.57267654473801     
 y(           3)=  -6.17277645686610     
 y(           4)=  -5.77328784212751     
 y(           5)=  -2.44604136584213     
 y(           6)=  0.339346383787519     
 y(           7)=   3.64922950132993     
 y(           8)=   8.41194269440747     
 y(           9)=   8.70457350837723     
 y(          10)=   8.99720816246373     
 y(          11)=   8.99720816246373     
             ***** Nkp(      2)=   80526.9775390625     *****
 y(           0)=  -7.87384149070998     
 y(           1)=  -7.77384262861692     
 y(           2)=  -7.67385284087623     
 y(           3)=  -7.27407012565421     
 y(           4)=  -6.87518502439682     
 y(           5)=  -3.75743996301063     
 y(           6)=  -2.23807467374087     
 y(           7)=  -2.14250281261541     
 y(           8)=  -3.23111558844155     
 y(           9)=  -3.30791098221849     
 y(          10)=  -3.38470907188850     
 y(          11)=  -3.38470907188850     
             ***** Nkp(      3)=   130680.053710938     *****
 y(           0)=  -3.00707576137097     
 y(           1)=  -2.90707690583002     
 y(           2)=  -2.80708712984465     
 y(           3)=  -2.40730059527169     
 y(           4)=  -2.00836837225431     
 y(           5)=   1.18125191726386     
 y(           6)=   2.71633590365441     
 y(           7)=   1.52469198879631     
 y(           8)=  -1.31736272225184     
 y(           9)=  -1.49639379071970     
 y(          10)=  -1.67542830772317     
 y(          11)=  -1.67542830772317     
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