doublerange.java

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package org.apache.commons.lang.math;

import java.io.Serializable;

/**
 * <p><code>DoubleRange</code> represents an inclusive range of <code>double</code>s.</p>
 *
 * @author Stephen Colebourne
 * @since 2.0
 * @version $Id: DoubleRange.java,v 1.5 2003/08/18 02:22:24 bayard Exp $
 */
public final class DoubleRange extends Range implements Serializable {
    
    private static final long serialVersionUID = 71849363892740L;

    /**
     * The minimum number in this range (inclusive).
     */
    private final double min;
    /**
     * The maximum number in this range (inclusive).
     */
    private final double max;
    
    /**
     * Cached output minObject (class is immutable).
     */
    private transient Double minObject = null;
    /**
     * Cached output maxObject (class is immutable).
     */
    private transient Double maxObject = null;
    /**
     * Cached output hashCode (class is immutable).
     */
    private transient int hashCode = 0;
    /**
     * Cached output toString (class is immutable).
     */
    private transient String toString = null;
    
    /**
     * <p>Constructs a new <code>DoubleRange</code> using the specified
     * number as both the minimum and maximum in this range.</p>
     *
     * @param number  the number to use for this range
     * @throws IllegalArgumentException if the number is <code>NaN</code>
     */
    public DoubleRange(double number) {
        super();
        if (Double.isNaN(number)) {
            throw new IllegalArgumentException("The number must not be NaN");
        }
        this.min = number;
        this.max = number;
    }

    /**
     * <p>Constructs a new <code>DoubleRange</code> using the specified
     * number as both the minimum and maximum in this range.</p>
     *
     * @param number  the number to use for this range, must not
     *  be <code>null</code>
     * @throws IllegalArgumentException if the number is <code>null</code>
     * @throws IllegalArgumentException if the number is <code>NaN</code>
     */
    public DoubleRange(Number number) {
        super();
        if (number == null) {
            throw new IllegalArgumentException("The number must not be null");
        }
        this.min = number.doubleValue();
        this.max = number.doubleValue();
        if (Double.isNaN(min) || Double.isNaN(max)) {
            throw new IllegalArgumentException("The number must not be NaN");
        }
        if (number instanceof Double) {
            this.minObject = (Double) number;
            this.maxObject = (Double) number;
        }
    }

    /**
     * <p>Constructs a new <code>DoubleRange</code> with the specified
     * minimum and maximum numbers (both inclusive).</p>
     * 
     * <p>The arguments may be passed in the order (min,max) or (max,min). The
     * getMinimum and getMaximum methods will return the correct values.</p>
     * 
     * @param number1  first number that defines the edge of the range, inclusive
     * @param number2  second number that defines the edge of the range, inclusive
     * @throws IllegalArgumentException if either number is <code>NaN</code>
     */
    public DoubleRange(double number1, double number2) {
        super();
        if (Double.isNaN(number1) || Double.isNaN(number2)) {
            throw new IllegalArgumentException("The numbers must not be NaN");
        }
        if (number2 < number1) {
            this.min = number2;
            this.max = number1;
        } else {
            this.min = number1;
            this.max = number2;
        }
    }

    /**
     * <p>Constructs a new <code>DoubleRange</code> with the specified
     * minimum and maximum numbers (both inclusive).</p>
     * 
     * <p>The arguments may be passed in the order (min,max) or (max,min). The
     * getMinimum and getMaximum methods will return the correct values.</p>
     *
     * @param number1  first number that defines the edge of the range, inclusive
     * @param number2  second number that defines the edge of the range, inclusive
     * @throws IllegalArgumentException if either number is <code>null</code>
     * @throws IllegalArgumentException if either number is <code>NaN</code>
     */
    public DoubleRange(Number number1, Number number2) {
        super();
        if (number1 == null || number2 == null) {
            throw new IllegalArgumentException("The numbers must not be null");
        }
        double number1val = number1.doubleValue();
        double number2val = number2.doubleValue();
        if (Double.isNaN(number1val) || Double.isNaN(number2val)) {
            throw new IllegalArgumentException("The numbers must not be NaN");
        }
        if (number2val < number1val) {
            this.min = number2val;
            this.max = number1val;
            if (number2 instanceof Double) {
                this.minObject = (Double) number2;
            }
            if (number1 instanceof Double) {
                this.maxObject = (Double) number1;
            }
        } else {
            this.min = number1val;
            this.max = number2val;
            if (number1 instanceof Double) {
                this.minObject = (Double) number1;
            }
            if (number2 instanceof Double) {
                this.maxObject = (Double) number2;
            }
        }
    }

    // Accessors
    //--------------------------------------------------------------------

    /**
     * <p>Returns the minimum number in this range.</p>
     *
     * @return the minimum number in this range
     */
    public Number getMinimumNumber() {
        if (minObject == null) {
            minObject = new Double(min);            
        }
        return minObject;
    }

    /**
     * <p>Gets the minimum number in this range as a <code>long</code>.</p>
     * 
     * <p>This conversion can lose information for large values or decimals.</p>
     *
     * @return the minimum number in this range
     */