stringutils.java

JAVA 文章管理系统源码

     * 
     * <pre>
     * StringUtils.indexOfAny(null, *)                     = -1
     * StringUtils.indexOfAny(*, null)                     = -1
     * StringUtils.indexOfAny(*, [])                       = -1
     * StringUtils.indexOfAny("zzabyycdxx", ["ab","cd"])   = 2
     * StringUtils.indexOfAny("zzabyycdxx", ["cd","ab"])   = 2
     * StringUtils.indexOfAny("zzabyycdxx", ["mn","op"])   = -1
     * StringUtils.indexOfAny("zzabyycdxx", ["zab","aby"]) = 1
     * StringUtils.indexOfAny("zzabyycdxx", [""])          = 0
     * StringUtils.indexOfAny("", [""])                    = 0
     * StringUtils.indexOfAny("", ["a"])                   = -1
     * </pre>
     * 
     * @param str  the String to check, may be null
     * @param searchStrs  the Strings to search for, may be null
     * @return the first index of any of the searchStrs in str, -1 if no match
     */
    public static int indexOfAny(String str, String[] searchStrs) {
        if ((str == null) || (searchStrs == null)) {
            return -1;
        }
        int sz = searchStrs.length;

        // String's can't have a MAX_VALUEth index.
        int ret = Integer.MAX_VALUE;

        int tmp = 0;
        for (int i = 0; i < sz; i++) {
            String search = searchStrs[i];
            if (search == null) {
                continue;
            }
            tmp = str.indexOf(search);
            if (tmp == -1) {
                continue;
            }

            if (tmp < ret) {
                ret = tmp;
            }
        }

        return (ret == Integer.MAX_VALUE) ? -1 : ret;
    }

    /**
     * <p>Find the latest index of any of a set of potential substrings.</p>
     *
     * <p>A <code>null</code> String will return <code>-1</code>.
     * A <code>null</code> search array will return <code>-1</code>.
     * A <code>null</code> or zero length search array entry will be ignored,
     * but a search array containing "" will return the length of <code>str</code> 
     * if <code>str</code> is not null. This method uses {@link String#indexOf(String)}</p>
     * 
     * <pre>
     * StringUtils.lastIndexOfAny(null, *)                   = -1
     * StringUtils.lastIndexOfAny(*, null)                   = -1
     * StringUtils.lastIndexOfAny(*, [])                     = -1
     * StringUtils.lastIndexOfAny(*, [null])                 = -1
     * StringUtils.lastIndexOfAny("zzabyycdxx", ["ab","cd"]) = 6
     * StringUtils.lastIndexOfAny("zzabyycdxx", ["cd","ab"]) = 6
     * StringUtils.lastIndexOfAny("zzabyycdxx", ["mn","op"]) = -1
     * StringUtils.lastIndexOfAny("zzabyycdxx", ["mn","op"]) = -1
     * StringUtils.lastIndexOfAny("zzabyycdxx", ["mn",""])   = 10
     * </pre>
     * 
     * @param str  the String to check, may be null
     * @param searchStrs  the Strings to search for, may be null
     * @return the last index of any of the Strings, -1 if no match
     */
    public static int lastIndexOfAny(String str, String[] searchStrs) {
        if ((str == null) || (searchStrs == null)) {
            return -1;
        }
        int sz = searchStrs.length;
        int ret = -1;
        int tmp = 0;
        for (int i = 0; i < sz; i++) {
            String search = searchStrs[i];
            if (search == null) {
                continue;
            }
            tmp = str.lastIndexOf(search);
            if (tmp > ret) {
                ret = tmp;
            }
        }
        return ret;
    }

    // Substring
    //-----------------------------------------------------------------------
    /**
     * <p>Gets a substring from the specified String avoiding exceptions.</p>
     *
     * <p>A negative start position can be used to start <code>n</code>
     * characters from the end of the String.</p>
     *
     * <p>A <code>null</code> String will return <code>null</code>.
     * An empty ("") String will return "".</p>
     * 
     * <pre>
     * StringUtils.substring(null, *)   = null
     * StringUtils.substring("", *)     = ""
     * StringUtils.substring("abc", 0)  = "abc"
     * StringUtils.substring("abc", 2)  = "c"
     * StringUtils.substring("abc", 4)  = ""
     * StringUtils.substring("abc", -2) = "bc"
     * StringUtils.substring("abc", -4) = "abc"
     * </pre>
     * 
     * @param str  the String to get the substring from, may be null
     * @param start  the position to start from, negative means
     *  count back from the end of the String by this many characters
     * @return substring from start position, <code>null</code> if null String input
     */
    public static String substring(String str, int start) {
        if (str == null) {
            return null;
        }

        // handle negatives, which means last n characters
        if (start < 0) {
            start = str.length() + start; // remember start is negative
        }

        if (start < 0) {
            start = 0;
        }
        if (start > str.length()) {
            return EMPTY;
        }

        return str.substring(start);
    }
    
    /**
     * <p>Gets a substring from the specified String avoiding exceptions.</p>
     *
     * <p>A negative start position can be used to start/end <code>n</code>
     * characters from the end of the String.</p>
     *
     * <p>The returned substring starts with the character in the <code>start</code>
     * position and ends before the <code>end</code> position. All postion counting is 
     * zero-based -- i.e., to start at the beginning of the string use 
     * <code>start = 0</code>. Negative start and end positions can be used to 
     * specify offsets relative to the end of the String.</p>
     *
     * <p>If <code>start</code> is not strictly to the left of <code>end</code>, ""
     * is returned.</p>
     * 
     * <pre>
     * StringUtils.substring(null, *, *)    = null
     * StringUtils.substring("", * ,  *)    = "";
     * StringUtils.substring("abc", 0, 2)   = "ab"
     * StringUtils.substring("abc", 2, 0)   = ""
     * StringUtils.substring("abc", 2, 4)   = "c"
     * StringUtils.substring("abc", 4, 6)   = ""
     * StringUtils.substring("abc", 2, 2)   = ""
     * StringUtils.substring("abc", -2, -1) = "b"
     * StringUtils.substring("abc", -4, 2)  = "ab"
     * </pre>
     * 
     * @param str  the String to get the substring from, may be null
     * @param start  the position to start from, negative means
     *  count back from the end of the String by this many characters
     * @param end  the position to end at (exclusive), negative means
     *  count back from the end of the String by this many characters
     * @return substring from start position to end positon,
     *  <code>null</code> if null String input
     */
    public static String substring(String str, int start, int end) {
        if (str == null) {
            return null;
        }

        // handle negatives
        if (end < 0) {
            end = str.length() + end; // remember end is negative
        }
        if (start < 0) {
            start = str.length() + start; // remember start is negative
        }

        // check length next
        if (end > str.length()) {
            end = str.length();
        }

        // if start is greater than end, return ""
        if (start > end) {
            return EMPTY;
        }

        if (start < 0) {
            start = 0;
        }
        if (end < 0) {
            end = 0;
        }

        return str.substring(start, end);
    }

    // Left/Right/Mid
    //-----------------------------------------------------------------------
    /**
     * <p>Gets the leftmost <code>len</code> characters of a String.</p>
     *
     * <p>If <code>len</code> characters are not available, or the
     * String is <code>null</code>, the String will be returned without
     * an exception. An exception is thrown if len is negative.</p>
     *
     * <pre>
     * StringUtils.left(null, *)    = null
     * StringUtils.left(*, -ve)     = ""
     * StringUtils.left("", *)      = ""
     * StringUtils.left("abc", 0)   = ""
     * StringUtils.left("abc", 2)   = "ab"
     * StringUtils.left("abc", 4)   = "abc"
     * </pre>
     * 
     * @param str  the String to get the leftmost characters from, may be null
     * @param len  the length of the required String, must be zero or positive
     * @return the leftmost characters, <code>null</code> if null String input
     */
    public static String left(String str, int len) {
        if (str == null) {
            return null;
        }
        if (len < 0) {
            return EMPTY;
        }
        if (str.length() <= len) {
            return str;
        } else {
            return str.substring(0, len);
        }
    }

    /**
     * <p>Gets the rightmost <code>len</code> characters of a String.</p>
     *
     * <p>If <code>len</code> characters are not available, or the String
     * is <code>null</code>, the String will be returned without an
     * an exception. An exception is thrown if len is negative.</p>
     *
     * <pre>
     * StringUtils.right(null, *)    = null
     * StringUtils.right(*, -ve)     = ""
     * StringUtils.right("", *)      = ""
     * StringUtils.right("abc", 0)   = ""
     * StringUtils.right("abc", 2)   = "bc"
     * StringUtils.right("abc", 4)   = "abc"
     * </pre>
     * 
     * @param str  the String to get the rightmost characters from, may be null
     * @param len  the length of the required String, must be zero or positive
     * @return the rightmost characters, <code>null</code> if null String input
     */
    public static String right(String str, int len) {
        if (str == null) {
            return null;
        }
        if (len < 0) {
            return EMPTY;
        }
        if (str.length() <= len) {
            return str;
        } else {
            return str.substring(str.length() - len);
        }
    }

    /**
     * <p>Gets <code>len</code> characters from the middle of a String.</p>
     *
     * <p>If <code>len</code> characters are not available, the remainder
     * of the String will be returned without an exception. If the
     * String is <code>null</code>, <code>null</code> will be returned.
     * An exception is thrown if len is negative.</p>
     *
     * <pre>
     * StringUtils.mid(null, *, *)    = null
     * StringUtils.mid(*, *, -ve)     = ""
     * StringUtils.mid("", 0, *)      = ""
     * StringUtils.mid("abc", 0, 2)   = "ab"
     * StringUtils.mid("abc", 0, 4)   = "abc"
     * StringUtils.mid("abc", 2, 4)   = "c"
     * StringUtils.mid("abc", 4, 2)   = ""
     * StringUtils.mid("abc", -2, 2)  = "ab"
     * </pre>
     * 
     * @param str  the String to get the characters from, may be null
     * @param pos  the position to start from, negative treated as zero
     * @param len  the length of the required String, must be zero or positive
     * @return the middle characters, <code>null</code> if null String input
     */
    public static String mid(String str, int pos, int len) {
        if (str == null) {
            return null;
        }
        if (len < 0 || pos > str.length()) {
            return EMPTY;
        }
        if (pos < 0) {
            pos = 0;
        }
        if (str.length() <= (pos + len)) {
            return str.substring(pos);
        } else {
            return str.substring(pos, pos + len);
        }
    }

    // SubStringAfter/SubStringBefore
    //-----------------------------------------------------------------------
    /**
     * <p>Gets the substring before the first occurance of a separator.
     * The separator is not returned.</p>
     *
     * <p>A <code>null</code> string input will return <code>null</code>.
     * An empty ("") string input will return the empty string.
     * A <code>null</code> separator will return the input string.</p>
     *
     * <pre>
     * StringUtils.substringBefore(null, *)      = null
     * StringUti