checkdifficulty.assert

一个开源测试项目的代码,用于测试模块间分离程度的

#if($item == "advice")
		int diffi;
		int result;
		diffi=mainForm.getDifficulty();
		result=new Integer($target);
		if((new Integer(diffi)).equals(result))
			$success
		else
			$failure
#end
#if($item == "finished")
#parse("repositories/assert.pct")
#end