userservice.java

《Ajax开发精要〉〉该书详细的介绍了关于Ajax和java相关的开发知识

package com.ajaxlab.ajax;

public class UserService {
	public UserService() {

	}

	public UserValue findUserByName(String username) throws Exception{
		UserValue user = null;
		if("jimmy".equalsIgnoreCase(username)) {
			user = new UserValue("jimmy","123456","[e-mail]");
			return user;
		}
		else return null;
	}

	public UserValue findUserByEmail(String email) throws Exception{
		UserValue user = null;
		if(email==null) return null;
		if((email.indexOf("@")!=-1)&&(email.indexOf(".")!=-1)) {
			if("[e-mail]".equalsIgnoreCase(email)) {
				user = new UserValue("jimmy","123456","[e-mail]");
				return user;
			}
			else return null;
		}
		else {
			throw new Exception("电子邮件格式错误。");
		}
	}
}