qyyecfc.cpp

求解以一次方程的小程序

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
	float a,b,c,x1,x2;
	cin>>a>>b>>c;
	x1=(-b+sqrt(b*b-4*a*c))/(2*a);
	x2=(-b-sqrt(b*b-4*a*c))/(2*a);
	cout<<"x1="<<x1<<endl;
	cout<<"x2="<<x2<<endl;
	return 0;
}