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📄 passworddemo.java

📁 这是一个英文版的《Java程序设计与问题解决》现在好多大学都当成教材
💻 JAVA
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import javax.swing.*;import java.awt.*;import java.awt.event.*;public class PasswordDemo {    public static void main(String[] argv) {        final JFrame f = new JFrame("PasswordDemo");        JLabel label = new JLabel("Enter the password: ");        JPasswordField passwordField = new JPasswordField(10);        passwordField.setEchoChar('#');        passwordField.addActionListener(new ActionListener() {            public void actionPerformed(ActionEvent e) {                JPasswordField input = (JPasswordField)e.getSource();                char[] password = input.getPassword();                if (isPasswordCorrect(password)) {                    JOptionPane.showMessageDialog(f,                        "Success! You typed the right password.");                } else {                    JOptionPane.showMessageDialog(f,                        "Invalid password. Try again.",                        "Error Message",                        JOptionPane.ERROR_MESSAGE);                }            }        });        JPanel contentPane = new JPanel(new BorderLayout());        contentPane.setBorder(BorderFactory.createEmptyBorder(20, 20, 20, 20));        contentPane.add(label, BorderLayout.WEST);        contentPane.add(passwordField, BorderLayout.CENTER);        f.setContentPane(contentPane);        f.addWindowListener(new WindowAdapter() {            public void windowClosing(WindowEvent e) { System.exit(0); }        });        f.pack();        f.setVisible(true);    }    private static boolean isPasswordCorrect(char[] input) {        char[] correctPassword = { 'b', 'u', 'g', 'a', 'b', 'o', 'o' };        if (input.length != correctPassword.length)            return false;        for (int i = 0;  i < input.length; i ++)            if (input[i] != correctPassword[i])                return false;        return true;    }}

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