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📄 sshdssg.c

📁 大名鼎鼎的远程登录软件putty的Symbian版源码
💻 C
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/* * DSS key generation. */#include "misc.h"#include "ssh.h"int dsa_generate(struct dss_key *key, int bits, progfn_t pfn,		 void *pfnparam){    Bignum qm1, power, g, h, tmp;    int progress;    /*     * Set up the phase limits for the progress report. We do this     * by passing minus the phase number.     *     * For prime generation: our initial filter finds things     * coprime to everything below 2^16. Computing the product of     * (p-1)/p for all prime p below 2^16 gives about 20.33; so     * among B-bit integers, one in every 20.33 will get through     * the initial filter to be a candidate prime.     *     * Meanwhile, we are searching for primes in the region of 2^B;     * since pi(x) ~ x/log(x), when x is in the region of 2^B, the     * prime density will be d/dx pi(x) ~ 1/log(B), i.e. about     * 1/0.6931B. So the chance of any given candidate being prime     * is 20.33/0.6931B, which is roughly 29.34 divided by B.     *     * So now we have this probability P, we're looking at an     * exponential distribution with parameter P: we will manage in     * one attempt with probability P, in two with probability     * P(1-P), in three with probability P(1-P)^2, etc. The     * probability that we have still not managed to find a prime     * after N attempts is (1-P)^N.     *      * We therefore inform the progress indicator of the number B     * (29.34/B), so that it knows how much to increment by each     * time. We do this in 16-bit fixed point, so 29.34 becomes     * 0x1D.57C4.     */    pfn(pfnparam, PROGFN_PHASE_EXTENT, 1, 0x2800);    pfn(pfnparam, PROGFN_EXP_PHASE, 1, -0x1D57C4 / 160);    pfn(pfnparam, PROGFN_PHASE_EXTENT, 2, 0x40 * bits);    pfn(pfnparam, PROGFN_EXP_PHASE, 2, -0x1D57C4 / bits);    /*     * In phase three we are finding an order-q element of the     * multiplicative group of p, by finding an element whose order     * is _divisible_ by q and raising it to the power of (p-1)/q.     * _Most_ elements will have order divisible by q, since for a     * start phi(p) of them will be primitive roots. So     * realistically we don't need to set this much below 1 (64K).     * Still, we'll set it to 1/2 (32K) to be on the safe side.     */    pfn(pfnparam, PROGFN_PHASE_EXTENT, 3, 0x2000);    pfn(pfnparam, PROGFN_EXP_PHASE, 3, -32768);    /*     * In phase four we are finding an element x between 1 and q-1     * (exclusive), by inventing 160 random bits and hoping they     * come out to a plausible number; so assuming q is uniformly     * distributed between 2^159 and 2^160, the chance of any given     * attempt succeeding is somewhere between 0.5 and 1. Lacking     * the energy to arrange to be able to specify this probability     * _after_ generating q, we'll just set it to 0.75.     */    pfn(pfnparam, PROGFN_PHASE_EXTENT, 4, 0x2000);    pfn(pfnparam, PROGFN_EXP_PHASE, 4, -49152);    pfn(pfnparam, PROGFN_READY, 0, 0);    /*     * Generate q: a prime of length 160.     */    key->q = primegen(160, 2, 2, NULL, 1, pfn, pfnparam);    /*     * Now generate p: a prime of length `bits', such that p-1 is     * divisible by q.     */    key->p = primegen(bits-160, 2, 2, key->q, 2, pfn, pfnparam);    /*     * Next we need g. Raise 2 to the power (p-1)/q modulo p, and     * if that comes out to one then try 3, then 4 and so on. As     * soon as we hit a non-unit (and non-zero!) one, that'll do     * for g.     */    power = bigdiv(key->p, key->q);    /* this is floor(p/q) == (p-1)/q */    h = bignum_from_long(1);    progress = 0;    while (1) {	pfn(pfnparam, PROGFN_PROGRESS, 3, ++progress);	g = modpow(h, power, key->p);	if (bignum_cmp(g, One) > 0)	    break;		       /* got one */	tmp = h;	h = bignum_add_long(h, 1);	freebn(tmp);    }    key->g = g;    freebn(h);    /*     * Now we're nearly done. All we need now is our private key x,     * which should be a number between 1 and q-1 exclusive, and     * our public key y = g^x mod p.     */    qm1 = copybn(key->q);    decbn(qm1);    progress = 0;    while (1) {	int i, v, byte, bitsleft;	Bignum x;	pfn(pfnparam, PROGFN_PROGRESS, 4, ++progress);	x = bn_power_2(159);	byte = 0;	bitsleft = 0;	for (i = 0; i < 160; i++) {	    if (bitsleft <= 0)		bitsleft = 8, byte = random_byte();	    v = byte & 1;	    byte >>= 1;	    bitsleft--;	    bignum_set_bit(x, i, v);	}	if (bignum_cmp(x, One) <= 0 || bignum_cmp(x, qm1) >= 0) {	    freebn(x);	    continue;	} else {	    key->x = x;	    break;	}    }    freebn(qm1);    key->y = modpow(key->g, key->x, key->p);    return 1;}

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