📄 analyze.c
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/* Analyze file differences for GNU DIFF. Copyright (C) 1988, 1989, 1992, 1993, 1994, 1995, 1998, 2001, 2002, 2004 Free Software Foundation, Inc. This file is part of GNU DIFF. GNU DIFF is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2, or (at your option) any later version. GNU DIFF is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program; see the file COPYING. If not, write to the Free Software Foundation, 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. *//* The basic algorithm is described in: "An O(ND) Difference Algorithm and its Variations", Eugene Myers, Algorithmica Vol. 1 No. 2, 1986, pp. 251-266; see especially section 4.2, which describes the variation used below. Unless the --minimal option is specified, this code uses the TOO_EXPENSIVE heuristic, by Paul Eggert, to limit the cost to O(N**1.5 log N) at the price of producing suboptimal output for large inputs with many differences. The basic algorithm was independently discovered as described in: "Algorithms for Approximate String Matching", E. Ukkonen, Information and Control Vol. 64, 1985, pp. 100-118. */#include "diff.h"#include <cmpbuf.h>#include <error.h>#include <file-type.h>#include <xalloc.h>static lin *xvec, *yvec; /* Vectors being compared. */static lin *fdiag; /* Vector, indexed by diagonal, containing 1 + the X coordinate of the point furthest along the given diagonal in the forward search of the edit matrix. */static lin *bdiag; /* Vector, indexed by diagonal, containing the X coordinate of the point furthest along the given diagonal in the backward search of the edit matrix. */static lin too_expensive; /* Edit scripts longer than this are too expensive to compute. */#define SNAKE_LIMIT 20 /* Snakes bigger than this are considered `big'. */struct partition{ lin xmid, ymid; /* Midpoints of this partition. */ bool lo_minimal; /* Nonzero if low half will be analyzed minimally. */ bool hi_minimal; /* Likewise for high half. */};/* Find the midpoint of the shortest edit script for a specified portion of the two files. Scan from the beginnings of the files, and simultaneously from the ends, doing a breadth-first search through the space of edit-sequence. When the two searches meet, we have found the midpoint of the shortest edit sequence. If FIND_MINIMAL is nonzero, find the minimal edit script regardless of expense. Otherwise, if the search is too expensive, use heuristics to stop the search and report a suboptimal answer. Set PART->(xmid,ymid) to the midpoint (XMID,YMID). The diagonal number XMID - YMID equals the number of inserted lines minus the number of deleted lines (counting only lines before the midpoint). Set PART->lo_minimal to true iff the minimal edit script for the left half of the partition is known; similarly for PART->hi_minimal. This function assumes that the first lines of the specified portions of the two files do not match, and likewise that the last lines do not match. The caller must trim matching lines from the beginning and end of the portions it is going to specify. If we return the "wrong" partitions, the worst this can do is cause suboptimal diff output. It cannot cause incorrect diff output. */static voiddiag (lin xoff, lin xlim, lin yoff, lin ylim, bool find_minimal, struct partition *part){ lin *const fd = fdiag; /* Give the compiler a chance. */ lin *const bd = bdiag; /* Additional help for the compiler. */ lin const *const xv = xvec; /* Still more help for the compiler. */ lin const *const yv = yvec; /* And more and more . . . */ lin const dmin = xoff - ylim; /* Minimum valid diagonal. */ lin const dmax = xlim - yoff; /* Maximum valid diagonal. */ lin const fmid = xoff - yoff; /* Center diagonal of top-down search. */ lin const bmid = xlim - ylim; /* Center diagonal of bottom-up search. */ lin fmin = fmid, fmax = fmid; /* Limits of top-down search. */ lin bmin = bmid, bmax = bmid; /* Limits of bottom-up search. */ lin c; /* Cost. */ bool odd = (fmid - bmid) & 1; /* True if southeast corner is on an odd diagonal with respect to the northwest. */ fd[fmid] = xoff; bd[bmid] = xlim; for (c = 1;; ++c) { lin d; /* Active diagonal. */ bool big_snake = false; /* Extend the top-down search by an edit step in each diagonal. */ fmin > dmin ? fd[--fmin - 1] = -1 : ++fmin; fmax < dmax ? fd[++fmax + 1] = -1 : --fmax; for (d = fmax; d >= fmin; d -= 2) { lin x, y, oldx, tlo = fd[d - 1], thi = fd[d + 1]; if (tlo >= thi) x = tlo + 1; else x = thi; oldx = x; y = x - d; while (x < xlim && y < ylim && xv[x] == yv[y]) ++x, ++y; if (x - oldx > SNAKE_LIMIT) big_snake = true; fd[d] = x; if (odd && bmin <= d && d <= bmax && bd[d] <= x) { part->xmid = x; part->ymid = y; part->lo_minimal = part->hi_minimal = true; return; } } /* Similarly extend the bottom-up search. */ bmin > dmin ? bd[--bmin - 1] = LIN_MAX : ++bmin; bmax < dmax ? bd[++bmax + 1] = LIN_MAX : --bmax; for (d = bmax; d >= bmin; d -= 2) { lin x, y, oldx, tlo = bd[d - 1], thi = bd[d + 1]; if (tlo < thi) x = tlo; else x = thi - 1; oldx = x; y = x - d; while (x > xoff && y > yoff && xv[x - 1] == yv[y - 1]) --x, --y; if (oldx - x > SNAKE_LIMIT) big_snake = true; bd[d] = x; if (!odd && fmin <= d && d <= fmax && x <= fd[d]) { part->xmid = x; part->ymid = y; part->lo_minimal = part->hi_minimal = true; return; } } if (find_minimal) continue; /* Heuristic: check occasionally for a diagonal that has made lots of progress compared with the edit distance. If we have any such, find the one that has made the most progress and return it as if it had succeeded. With this heuristic, for files with a constant small density of changes, the algorithm is linear in the file size. */ if (200 < c && big_snake && speed_large_files) { lin best = 0; for (d = fmax; d >= fmin; d -= 2) { lin dd = d - fmid; lin x = fd[d]; lin y = x - d; lin v = (x - xoff) * 2 - dd; if (v > 12 * (c + (dd < 0 ? -dd : dd))) { if (v > best && xoff + SNAKE_LIMIT <= x && x < xlim && yoff + SNAKE_LIMIT <= y && y < ylim) { /* We have a good enough best diagonal; now insist that it end with a significant snake. */ int k; for (k = 1; xv[x - k] == yv[y - k]; k++) if (k == SNAKE_LIMIT) { best = v; part->xmid = x; part->ymid = y; break; } } } } if (best > 0) { part->lo_minimal = true; part->hi_minimal = false; return; } best = 0; for (d = bmax; d >= bmin; d -= 2) { lin dd = d - bmid; lin x = bd[d]; lin y = x - d; lin v = (xlim - x) * 2 + dd; if (v > 12 * (c + (dd < 0 ? -dd : dd))) { if (v > best && xoff < x && x <= xlim - SNAKE_LIMIT && yoff < y && y <= ylim - SNAKE_LIMIT) { /* We have a good enough best diagonal; now insist that it end with a significant snake. */ int k; for (k = 0; xv[x + k] == yv[y + k]; k++) if (k == SNAKE_LIMIT - 1) { best = v; part->xmid = x; part->ymid = y; break; } } } } if (best > 0) { part->lo_minimal = false; part->hi_minimal = true; return; } } /* Heuristic: if we've gone well beyond the call of duty, give up and report halfway between our best results so far. */ if (c >= too_expensive) { lin fxybest, fxbest; lin bxybest, bxbest; fxbest = bxbest = 0; /* Pacify `gcc -Wall'. */ /* Find forward diagonal that maximizes X + Y. */ fxybest = -1; for (d = fmax; d >= fmin; d -= 2) { lin x = MIN (fd[d], xlim); lin y = x - d; if (ylim < y) x = ylim + d, y = ylim; if (fxybest < x + y) { fxybest = x + y; fxbest = x; } } /* Find backward diagonal that minimizes X + Y. */ bxybest = LIN_MAX; for (d = bmax; d >= bmin; d -= 2) { lin x = MAX (xoff, bd[d]); lin y = x - d; if (y < yoff) x = yoff + d, y = yoff; if (x + y < bxybest) { bxybest = x + y; bxbest = x; } } /* Use the better of the two diagonals. */ if ((xlim + ylim) - bxybest < fxybest - (xoff + yoff)) { part->xmid = fxbest; part->ymid = fxybest - fxbest; part->lo_minimal = true; part->hi_minimal = false; } else { part->xmid = bxbest; part->ymid = bxybest - bxbest; part->lo_minimal = false; part->hi_minimal = true; } return; } }}/* Compare in detail contiguous subsequences of the two files which are known, as a whole, to match each other. The results are recorded in the vectors files[N].changed, by storing 1 in the element for each line that is an insertion or deletion. The subsequence of file 0 is [XOFF, XLIM) and likewise for file 1. Note that XLIM, YLIM are exclusive bounds. All line numbers are origin-0 and discarded lines are not counted. If FIND_MINIMAL, find a minimal difference no matter how expensive it is. */static voidcompareseq (lin xoff, lin xlim, lin yoff, lin ylim, bool find_minimal){ lin const *xv = xvec; /* Help the compiler. */ lin const *yv = yvec; /* Slide down the bottom initial diagonal. */ while (xoff < xlim && yoff < ylim && xv[xoff] == yv[yoff]) ++xoff, ++yoff; /* Slide up the top initial diagonal. */ while (xlim > xoff && ylim > yoff && xv[xlim - 1] == yv[ylim - 1]) --xlim, --ylim; /* Handle simple cases. */ if (xoff == xlim) while (yoff < ylim) files[1].changed[files[1].realindexes[yoff++]] = 1; else if (yoff == ylim) while (xoff < xlim) files[0].changed[files[0].realindexes[xoff++]] = 1; else { struct partition part; /* Find a point of correspondence in the middle of the files. */ diag (xoff, xlim, yoff, ylim, find_minimal, &part); /* Use the partitions to split this problem into subproblems. */ compareseq (xoff, part.xmid, yoff, part.ymid, part.lo_minimal); compareseq (part.xmid, xlim, part.ymid, ylim, part.hi_minimal); }}/* Discard lines from one file that have no matches in the other file. A line which is discarded will not be considered by the actual comparison algorithm; it will be as if that line were not in the file. The file's `realindexes' table maps virtual line numbers (which don't count the discarded lines) into real line numbers; this is how the actual comparison algorithm produces results that are comprehensible when the discarded lines are counted. When we discard a line, we also mark it as a deletion or insertion so that it will be printed in the output. */static voiddiscard_confusing_lines (struct file_data filevec[]){ int f; lin i; char *discarded[2]; lin *equiv_count[2]; lin *p; /* Allocate our results. */ p = xmalloc ((filevec[0].buffered_lines + filevec[1].buffered_lines) * (2 * sizeof *p)); for (f = 0; f < 2; f++) { filevec[f].undiscarded = p; p += filevec[f].buffered_lines; filevec[f].realindexes = p; p += filevec[f].buffered_lines; } /* Set up equiv_count[F][I] as the number of lines in file F that fall in equivalence class I. */ p = zalloc (filevec[0].equiv_max * (2 * sizeof *p)); equiv_count[0] = p; equiv_count[1] = p + filevec[0].equiv_max; for (i = 0; i < filevec[0].buffered_lines; ++i) ++equiv_count[0][filevec[0].equivs[i]]; for (i = 0; i < filevec[1].buffered_lines; ++i) ++equiv_count[1][filevec[1].equivs[i]]; /* Set up tables of which lines are going to be discarded. */ discarded[0] = zalloc (filevec[0].buffered_lines + filevec[1].buffered_lines); discarded[1] = discarded[0] + filevec[0].buffered_lines; /* Mark to be discarded each line that matches no line of the other file. If a line matches many lines, mark it as provisionally discardable. */ for (f = 0; f < 2; f++) { size_t end = filevec[f].buffered_lines; char *discards = discarded[f]; lin *counts = equiv_count[1 - f]; lin *equivs = filevec[f].equivs; size_t many = 5; size_t tem = end / 64; /* Multiply MANY by approximate square root of number of lines. That is the threshold for provisionally discardable lines. */ while ((tem = tem >> 2) > 0) many *= 2; for (i = 0; i < end; i++) { lin nmatch; if (equivs[i] == 0) continue; nmatch = counts[equivs[i]]; if (nmatch == 0) discards[i] = 1; else if (nmatch > many) discards[i] = 2; } } /* Don't really discard the provisional lines except when they occur in a run of discardables, with nonprovisionals at the beginning and end. */ for (f = 0; f < 2; f++) { lin end = filevec[f].buffered_lines; register char *discards = discarded[f]; for (i = 0; i < end; i++) { /* Cancel provisional discards not in middle of run of discards. */ if (discards[i] == 2) discards[i] = 0; else if (discards[i] != 0) { /* We have found a nonprovisional discard. */ register lin j; lin length; lin provisional = 0; /* Find end of this run of discardable lines. Count how many are provisionally discardable. */ for (j = i; j < end; j++) { if (discards[j] == 0) break; if (discards[j] == 2) ++provisional; } /* Cancel provisional discards at end, and shrink the run. */ while (j > i && discards[j - 1] == 2) discards[--j] = 0, --provisional; /* Now we have the length of a run of discardable lines whose first and last are not provisional. */ length = j - i; /* If 1/4 of the lines in the run are provisional, cancel discarding of all provisional lines in the run. */ if (provisional * 4 > length) { while (j > i) if (discards[--j] == 2) discards[j] = 0; } else { register lin consec; lin minimum = 1; lin tem = length >> 2; /* MINIMUM is approximate square root of LENGTH/4. A subrun of two or more provisionals can stand when LENGTH is at least 16. A subrun of 4 or more can stand when LENGTH >= 64. */ while (0 < (tem >>= 2)) minimum <<= 1; minimum++; /* Cancel any subrun of MINIMUM or more provisionals within the larger run. */ for (j = 0, consec = 0; j < length; j++) if (discards[i + j] != 2) consec = 0; else if (minimum == ++consec) /* Back up to start of subrun, to cancel it all. */ j -= consec; else if (minimum < consec) discards[i + j] = 0; /* Scan from beginning of run until we find 3 or more nonprovisionals in a row or until the first nonprovisional at least 8 lines in. Until that point, cancel any provisionals. */ for (j = 0, consec = 0; j < length; j++) { if (j >= 8 && discards[i + j] == 1) break; if (discards[i + j] == 2)
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