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📄 useraction.java

📁 ajax+jsp实现的一个例子
💻 JAVA
字号:
/*
 * Generated by MyEclipse Struts
 * Template path: templates/java/JavaClass.vtl
 */
package com.yourcompany.struts.action;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.json.JSONException;
import org.json.JSONObject;

/** 
 * MyEclipse Struts
 * Creation date: 01-10-2008
 * 
 * XDoclet definition:
 * @struts.action validate="true"
 */
public class UserAction extends Action {
	/*
	 * Generated Methods
	 */

	/** 
	 * Method execute
	 * @param mapping
	 * @param form
	 * @param request
	 * @param response
	 * @return ActionForward
	 */
	public ActionForward execute(ActionMapping mapping, ActionForm form,
			HttpServletRequest request, HttpServletResponse response) {
		String result="";
    	//JSONArray _array = new JSONArray();
    	
    	JSONObject _user = new JSONObject();
		
		try {
			_user.append("gender","男");
			_user.append("age","18");
			_user.append("name","张三1");
			response.setCharacterEncoding("utf-8");
			response.getOutputStream().print(_user.toString());
		} catch (Exception e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}
		
		//_array.put(_user);
		
		//JSONObject _users = new JSONObject();
		//out.print(_users.put(_array));
		//result = new JSONObject().put("user",_user).toString();
		
		return mapping.findForward("tree");
	}
}

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