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📄 stdafx.cpp

📁 类似于股市K线技术分析的系统源码
💻 CPP
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// stdafx.cpp : source file that includes just the standard includes
//	LastProject.pch will be the pre-compiled header
//	stdafx.obj will contain the pre-compiled type information

#include "stdafx.h"


int GetChartCount()
{
	CDatabase db;
	CRecordset	rs;
	CString VAL;
	try
	{
		db.OpenEx(CHARTDSN,CDatabase::noOdbcDialog);
		rs.m_pDatabase = &db;
		rs.Open(CRecordset::snapshot,"SELECT count(*) as count FROM ChartTab");
		//读取分析图区域参数
		rs.GetFieldValue("count",VAL);
	}catch(CDBException *e)
	{
		e->ReportError();
	}
	if(rs.IsOpen())	rs.Close();
	if(db.IsOpen()) db.Close();
	return atoi(VAL);
}



void ReMoveWindow(CRect & rect)
{
	CDatabase db;
	CRecordset	rs;
	CString VAL,SQL;
	SQL.Format("SELECT * FROM ChartTab WHERE ChartNo=%d",atoi(__argv[1]));
	try
	{
		db.OpenEx(CHARTDSN,CDatabase::noOdbcDialog);
		rs.m_pDatabase = &db;
		rs.Open(CRecordset::snapshot,SQL);
		//读取分析图区域参数
		rs.GetFieldValue("Left",VAL);
		rect.left = atoi(VAL);
		rs.GetFieldValue("Top",VAL);
		rect.top = atoi(VAL);
		rs.GetFieldValue("Width",VAL);
		rect.right = atoi(VAL) + rect.left;
		rs.GetFieldValue("Height",VAL);
		rect.bottom = atoi(VAL) + rect.top;
	}catch(CDBException *e)
	{
		e->ReportError();
	}
	if(rs.IsOpen())	rs.Close();
	if(db.IsOpen()) db.Close();
}

CString CodeToName(CString code)
{
	CString name;
	switch(atoi(code)/100)
	{
	case 12:name = "英镑/";break;
	case 13:name = "港币/";break;
	case 14:name = "美元/";break;
	case 15:name = "瑞郎/";break;
	case 18:name = "新元/";break;
	case 27:name = "日元/";break;
	case 28:name = "加元/";break;
	case 29:name = "澳元/";break;
	case 38:name = "欧元/";break;
	}

	switch(atoi(code)%100)
	{
	case 12:name += "英镑";break;
	case 13:name += "港币";break;
	case 14:name += "美元";break;
	case 15:name += "瑞郎";break;
	case 18:name += "新元";break;
	case 27:name += "日元";break;
	case 28:name += "加元";break;
	case 29:name += "澳元";break;
	case 38:name += "欧元";break;
	}
	return name;
}

double SMA(double X,int N,int M,double SMA)
{
	return (M * X + (N - M) * SMA) / N;
}

double EMA(double X,int N,double EMA)
{
	return (2 * X + (N - 1) * EMA) / (N + 1);
}

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