fig08_08.cpp

来自「经典书籍源代码啊。。。第三版。。。数据结构与算法分析——C++描述(第3版).」· C++ 代码 · 共 12 行

/**
 * Union two disjoint sets.
 * For simplicity, we assume root1 and root2 are distinct
 * and represent set names.
 * root1 is the root of set 1.
 * root2 is the root of set 2.
 */
void DisjSets::unionSets( int root1, int root2 )
{
    s[ root2 ] = root1;
}