receivexmlservlet.java

《深入浅出Ajax》 源代码

package ajax;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.doc.Document;
import org.w3c.doc.NodeList;
import org.xml.sax.SAXException;
public class ReceiveXmlServlet extends HttpServlet{
	protected void doPost(HttpServletRequest request,HttpServletResponse response)
		throws ServletException,IOException {
		StringBuffer xml = new StringBuffer();
		String line = null;
		//从request将xml内容读到StringBuffer对象xml中
		try
		{
			BufferedReader reader = request.getReader();
			while((line = reader.readLine())!=null) {
				xml.append(line);
			}
		} catch(IOException ex) {
			System.out.println("读取XML文件过程发生错误!描述:"+ex.toString());
		}
		//从StringBuffer对象xml中生成Document对象,即得到了客户端提交过来的xml文件
		Document xmlDoc = null;
		try
		{
			xmlDoc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new ByteArrayInputStream(xml.toString().getBytes()));

		}
		catch (ParserConfigurationException ex)
		{
			System.out.println("解析XML文件过程中发生错误!描述:"+ex.toString());
		}
	}
}