checkuser.js

来自「类似xici的一个交流社区网站,jsp+mssql2000(sp4)开发,内含存」· JavaScript 代码 · 共 81 行

function goCheck()
		{
			document.form.username.value=CollapseWhitespace(document.form.username.value);
			if(document.form.username.value.length == 0)
			{
				alert('\n请输入您的注册姓名!');
				document.form.username.focus();
				return false
			}
			window.location = "server.jsp?action=usertest&username="+form.username.value+"&sendemail="+form.sendemail.value;
		}
		function CheckForm()
		{
			document.form.username.value=CollapseWhitespace(document.form.username.value);
			if(document.form.username.value.length == 0)
			{
				alert('\n请输入您的注册姓名!');
				document.form.username.focus();
				return false
			}			
			
            document.form.password.value=CollapseWhitespace(document.form.password.value);
			if(document.form.password.value.length == 0)
			{
				alert('\n请输入您的密码!');
				document.form.password.focus();
				return false
			}
			
            document.form.rpassword.value=CollapseWhitespace(document.form.rpassword.value);
			if(document.form.rpassword.value.length == 0)
			{
				alert('\n请输入重复输入您的密码!');
				document.form.rpassword.focus();
				return false
			}			
			
			if(document.form.password.value.length != document.form.rpassword.value.length)
			{
				alert('\n您两次输入的密码不一致请重新输入!');
				document.form.password.value="";
				document.form.rpassword.value="";
				document.form.password.focus();
				return false						
			}
			
			document.form.sendemail.value=CollapseWhitespace(document.form.sendemail.value);
			if(document.form.sendemail.value.length == 0)
			{
				alert('\n请输入您的注册信箱!');
				document.form.sendemail.focus();
				return false
			}

			if(!isEmail(document.form.sendemail.value))
			{
				alert('\n您的E-Mail输入错误，请重新输入您的注册信箱!');
				document.form.sendemail.focus();
				return false
			}
		return true
		}

		function CollapseWhitespace(str)
		{
			return str.replace(/\s+/g," ").replace(/^ /,"").replace(/ $/,"");
		}

		function isEmail(theStr)
		{
			var atIndex = theStr.indexOf("@");
			var dotIndex = theStr.indexOf(".",atIndex);
			var flag = true;

			theSub = theStr.substring(0,dotIndex+1);
			if	((atIndex<1) ||	(atIndex !=	theStr.lastIndexOf("@")) ||	(dotIndex <	(atIndex + 2)) || (theStr.length <=	theSub.length))
			{flag = false;}
			else
			{flag = true;}
			return (flag);
		}