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📄 cyclic_4th_order_cumulant.m

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function C4=cyclic_4th_order_cumulant(x1,x2,x3,x4,alpha,max_tau)%% CYCLIC_4TH_ORDER_CUMULANT%              %              calculates the cyclic fourth order cumulant of %              three signals x1,x2,x3,x4 at frequency alpha%             %              C3(k*alpha,tau1,tau2,tau3)=E{(x1(t)-E{x1(t)}) *%                                      (x2(t+tau1)-E{x2(t+tau1)} *%             			       (x3(t+tau2)-E{x3(t+tau2)} *%             			       (x4(t+tau3)-E{x4(t+tau3)} *%                                      exp(-jk(alpha)t)  }%              for k=0 ... 1/alpha%             %% USAGE%              C3=cyclic_4th_order_cumulant(x,y,alpha,max_tau)%% File: cyclic_4th_order_cumulant.m% Last Revised: 25/11/97% Created: 25/11/97% Author: Andrew C. McCormick% (C) University of Strathclyde% Simple error checksif nargin~=6  error('Incorrect number of arguments for function cyclic_4th_order_cumulant');endif alpha>2*pi  error('Cyclic frequency must be less than 2 pi in function cyclic_4th_order_cumulant');end% Remove cyclic mean from signalscmx1=cyclic_mean(x1,alpha);cmx2=cyclic_mean(x2,alpha);cmx3=cyclic_mean(x3,alpha);cmx4=cyclic_mean(x4,alpha);lx=length(x1);t=0:lx-1;T=ceil(2*pi/alpha)-1;for k=1:lx  x1(k)=x1(k)-1/(2*pi)*sum(cmx1.*exp(j*alpha*(0:T)*(k-1)));  x2(k)=x2(k)-1/(2*pi)*sum(cmx2.*exp(j*alpha*(0:T)*(k-1)));  x3(k)=x3(k)-1/(2*pi)*sum(cmx3.*exp(j*alpha*(0:T)*(k-1)));  x4(k)=x4(k)-1/(2*pi)*sum(cmx4.*exp(j*alpha*(0:T)*(k-1)));endC4=zeros(max_tau,max_tau,max_tau,T+1);ix=1:lx-max_tau-1;for tau1=0:max_tau  for tau2=0:max_tau    for tau3=0:max_tau      for k=0:T	M4=mean(x1(ix).*x2(tau1+ix).*x3(tau2+ix) ...	    .*x4(tau3+ix).*exp(j*k*alpha*t(ix)));	c2_12=mean(x1(ix).*x2(tau1+ix).*exp(j*k*alpha*t(ix)));	c2_34=mean(x3(tau2+ix).*x4(tau3+ix).*exp(j*k*alpha*t(ix)));	c2_13=mean(x1(ix).*x3(tau2+ix).*exp(j*k*alpha*t(ix)));	c2_24=mean(x2(tau1+ix).*x4(tau3+ix).*exp(j*k*alpha*t(ix)));	c2_14=mean(x1(ix).*x4(tau3+ix).*exp(j*k*alpha*t(ix)));	c2_23=mean(x2(tau1+ix).*x3(tau2+ix).*exp(j*k*alpha*t(ix)));	C4(tau1+1,tau2+1,tau3+1,k+1)=M4-c2_12*c2_34-c2_13*c2_24-c2_14*c2_23;      end    end  endend

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