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📄 贪心算法解决磁盘文件最优存储问题-一品浓茶 - 新浪blog.htm

📁 这是一个关于磁盘文件最优存储问题
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  XML:LANG="EN-US">p[]</SPAN><SPAN style="FONT-FAMILY: 宋体">按非递增序列排列</SPAN><SPAN 
  lang=EN-US XML:LANG="EN-US">p[k[1]]&gt;=p[k[2]]</SPAN><SPAN 
  style="FONT-FAMILY: 宋体">……</SPAN><SPAN lang=EN-US 
  XML:LANG="EN-US">&gt;=p[k[n]];</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 42pt"><SPAN lang=EN-US 
  XML:LANG="EN-US">//</SPAN> <SPAN style="FONT-FAMILY: 宋体">这里</SPAN><SPAN 
  lang=EN-US XML:LANG="EN-US">k1.k2</SPAN><SPAN 
  style="FONT-FAMILY: 宋体">是</SPAN><SPAN lang=EN-US 
  XML:LANG="EN-US">1</SPAN><SPAN style="FONT-FAMILY: 宋体">,</SPAN><SPAN 
  lang=EN-US XML:LANG="EN-US">2</SPAN><SPAN 
  style="FONT-FAMILY: 宋体">……</SPAN><SPAN lang=EN-US 
  XML:LANG="EN-US">n</SPAN><SPAN style="FONT-FAMILY: 宋体">的某一排列</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  x[n/2]=k[1];</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  r=n/2+1;</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  l=n/2-1;</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  for(i=2,i&lt;=n,i+=2)</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
{</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  x[r]=k[i];</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  r++;</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
}</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  for(i=3,i&lt;=n,i+=2)</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
{</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  x[l]=k[i];</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
  l--;</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US"><SPAN>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</SPAN> 
}</SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt"><SPAN lang=EN-US 
  XML:LANG="EN-US">}<SPAN>&nbsp;&nbsp;&nbsp;&nbsp;</SPAN></SPAN></P>
  <P class=MsoNormal style="TEXT-INDENT: 21pt">&nbsp;</P></DIV>
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