📄 d6r8.cpp
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#include <iostream.h>
#include <math.h>
#include <iomanip.h>
#include <stdlib.h>
static double r[98];
static int iff,ix1,ix2,ix3;
double ran1(int& idum)
{
double rm1,rm2,t;
int m1,m2,m3,ia1,ia2,ia3,ic1,ic2,ic3,j;
m1 = 259200, ia1 = 7141, ic1 = 54773, rm1 = 0.0000038580247,
m2 = 134456, ia2 = 8121, ic2 = 28411, rm2 = 0.0000074373773,
m3 = 243000, ia3= 4561, ic3 = 51349;
if ((idum < 0) || (iff == 0))
{
iff = 1;
ix1 = (ic1 - idum) % m1;
ix1 = (ia1 * ix1 + ic1) % m1;
ix2 = ix1 % m2;
ix1 = (ia1 * ix1 + ic1) % m1;
ix3 = ix1 % m3;
for (j = 1; j<=97; j++)
{
ix1 = (ia1 * ix1 + ic1)% m1;
ix2 = (ia2 * ix2 + ic2)% m2;
r[j] = (double(ix1) + double(ix2) * rm2) * rm1;
}
idum = 1;
}
ix1 = (ia1 * ix1 + ic1) % m1;
ix2 = (ia2 * ix2 + ic2) % m2;
ix3 = (ia3 * ix3 + ic3) % m3;
j = 1 + int((97 * ix3) / m3);
if ((j > 97) || (j < 1))
{
cout<< "abnormal exit"<<endl;
return 1;
}
t = r[j];
r[j] = (float(ix1) + float(ix2) * rm2) * rm1;
return t;
}
double gammln(double xx)
{
int j;
double cof[6],stp,half,one,fpf,x,tmp,ser,temp;
cof[1] = 76.18009173;
cof[2] = -86.50532033;
cof[3] = 24.01409822;
cof[4] = -1.231739516;
cof[5] = 0.00120858003;
cof[6] = -0.00000536382;
stp = 2.50662827465;
half = 0.5;
one = 1.0;
fpf = 5.5;
x = xx - one;
tmp = x + fpf;
tmp = (x + half) * log(tmp) - tmp;
ser = one;
for (j = 1;j<=6;j++)
{
x = x + one;
ser = ser + cof[j] / x;
}
temp = tmp + log(stp * ser);
return temp;
}
double poidev(int xm, int &idum)
{
double pi,g,em,t,sq,alxm,y,dum,temp;
int oldm=0;
pi = 3.141592654;
if (xm < 12)
{
if (xm != oldm)
{
oldm = xm;
g = exp(-xm);
}
em = -1.0;
t = 1.0;
do
{
em = em + 1.0;
t = t * ran1(idum);
}
while (t > g);
}
else
{
if (xm != oldm)
{
oldm = xm;
sq =sqrt(2.0 * xm);
alxm = log(xm);
g = xm * alxm - gammln(xm + 1.0);
}
do
{
do
{
y = tan(pi * ran1(idum));
em = sq * y + xm;
}
while (em < 0.0);
em = int(em);
dum = em * alxm - gammln(em + 1.0) - g;
t = 0.9 * (1.0 + y *y) * exp(dum);
}
while (ran1(idum) > t);
}
temp = em;
return temp;
}
void main()
{
//program d6r8
//driver for routine poidev
int idum,n = 20, npts = 10000, iscal = 200, llen = 50,xm,klim,i,j,k,m;
double dist[21];
char text[50];
idum = -13;
do
{
for (j = 1; j<=21; j++)
dist[j] = 0.0;
cout<<"Order of Poisson distribution [n=1..20] -1 to end."<<endl;
xm = 5;
cout<<xm<<endl;
if (xm <= 0) exit(1);
}
while (xm > 20);
for (i = 1; i<=npts; i++)
{
j = int(poidev(xm, idum)) + 1;
if ((j >= 1) && (j <= 21)) dist[j] = dist[j] + 1;
}
cout<< "Poisson distribution deviate, order "<<xm<<"of "<< npts<< " points"<<endl;
cout<< " x p[x] graph:"<<endl;
for (j = 1; j<=20; j++)
{
dist[j] = dist[j] / npts;
for (k = 0; k<=50; k++)
text[k] =' ';
klim = int(iscal * dist[j]);
if (klim > llen) klim = llen;
for (k = 1; k<=klim; k++)
text[k] = '*';
cout<< setw(5)<<float(j);
cout<< setw(10)<<dist[j]<<" ";
for (m = 1; m<=50; m++)
cout<< text[m];
cout<<endl;
}
}
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