📄 d1r4.cpp
字号:
#include "iostream.h"
#include "math.h"
void pendag(double a[], double b[], double c[], double d[], double e[], double r[], double u[], int n)
{
int k;
double w[100], beta[100], alpha[100], cg[100], h[100];
w[1] = c[1];
beta[1] = 0.0;
beta[2] = d[1] / w[1];
alpha[1] = 0.0;
alpha[2] = e[1] / w[1];
alpha[n] = 0.0;
alpha[n + 1] = 0.0;
for (k = 2; k<=n; k++)
{
cg[k] = b[k] - a[k] * beta[k - 1];
w[k] = c[k] - a[k] * alpha[k - 1] - cg[k] * beta[k];
if (w[k] == 0.0)
{
cout<< " w[k]=0.0 in pendag"<<endl;
}
beta[k + 1] = (d[k] - cg[k] * alpha[k]) / w[k];
alpha[k + 1] = e[k] / w[k];
}
h[1] = 0.0;
h[2] = r[1] / w[1];
for (k = 2; k<=n; k++)
{
h[k + 1] = (r[k] - a[k] * h[k - 1] - cg[k] * h[k]) / w[k];
}
u[n] = h[n + 1];
u[n - 1] = h[n] - beta[n] * u[n];
for (k = n - 2; k>=1; k--)
{
u[k] = h[k + 1] - beta[k + 1] * u[k + 1] - alpha[k + 1] * u[k + 2];
}
}
void main()
{
//program d1r4
//driver program for routine pendag
int i,j,l,n = 7;
double a[8], b[8], c[8], d[8], e[8], r[8], u[8], a1[8][8], x[8];
//输入已知的方程组的系数矩阵
for (i = 1; i<=n; i++)
{
for (j = 1; j<=n; j++)
{
a1[i][j] = 0;
}
}
a1[1][1] = 4; a1[1][2] = 1; a1[1][3] = 1;
a1[2][1] = 1; a1[2][2] = 5; a1[2][3] = 2; a1[2][4] = 2;
a1[3][1] = 1; a1[3][2] = 2; a1[3][3] = 6; a1[3][4] = 3; a1[3][5] = 3;
a1[4][2] = 2; a1[4][3] = 3; a1[4][4] = 7; a1[4][5] = 4; a1[4][6] = 4;
a1[5][3] = 3; a1[5][4] = 4; a1[5][5] = 8; a1[5][6] = 5; a1[5][7] = 5;
a1[6][4] = 4; a1[6][5] = 5; a1[6][6] = 9; a1[6][7] = 6;
a1[7][5] = 5; a1[7][6] = 6; a1[7][7] = 10;
//输入已知的方程组的右端向量
r[1] = 1; r[2] = 2; r[3] = 3;
r[4] = 4; r[5] = 5; r[6] = 6;
r[7] = 7;
cout<<endl;
cout<<"已知的方程组的右端向量"<<endl;
cout.width(10); cout<<r[1]<<endl;
cout.width(10); cout<<r[2]<<endl;
cout.width(10); cout<<r[3]<<endl;
cout.width(10); cout<<r[4]<<endl;
cout.width(10); cout<<r[5]<<endl;
cout.width(10); cout<<r[6]<<endl;
cout.width(10); cout<<r[7]<<endl;
for (i = 3; i<=n; i++)
{
a[i] = a1[i][i - 2];
}
for (i = 2; i<=n; i++)
{
b[i] = a1[i][i - 1];
}
for (i = 1; i<=n-1; i++)
{
d[i] = a1[i][i + 1];
}
for (i = 1; i<=n-2; i++)
{
e[i] = a1[i][i + 2];
}
for (i = 1; i<=n; i++)
{
c[i] = a1[i][i];
}
pendag(a, b, c, d, e, r, u, n);
cout<<endl;
cout<<"计算出的方程组的解"<<endl;
cout.width(14); cout<<u[1]<<endl;
cout.width(14); cout<<u[2]<<endl;
cout.width(14); cout<<u[3]<<endl;
cout.width(14); cout<<u[4]<<endl;
cout.width(14); cout<<u[5]<<endl;
cout.width(14); cout<<u[6]<<endl;
cout.width(14); cout<<u[7]<<endl;
//将计算出的解乘以系数矩阵,以验证计算结果正确
for (l = 1; l<=n; l++)
{
x[l] = 0.0;
for (j = 1; j<=n; j++)
{
x[l] = x[l] + a1[l][j] * u[j];
}
}
cout<<endl;
cout<<"计算出的解乘以系数矩阵的结果"<<endl;
cout.width(10); cout<<x[1]<<endl;
cout.width(10); cout<<x[2]<<endl;
cout.width(10); cout<<x[3]<<endl;
cout.width(10); cout<<x[4]<<endl;
cout.width(10); cout<<x[5]<<endl;
cout.width(10); cout<<x[6]<<endl;
cout.width(10); cout<<x[7]<<endl;
}
⌨️ 快捷键说明
复制代码
Ctrl + C
搜索代码
Ctrl + F
全屏模式
F11
切换主题
Ctrl + Shift + D
显示快捷键
?
增大字号
Ctrl + =
减小字号
Ctrl + -