inverse.c

来自「[Game.Programming].Academic - Graphics G」· C语言 代码 · 共 142 行

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#include "GraphicsGems.h"#include <stdio.h>/**** * * affine_matrix4_inverse * * Computes the inverse of a 3D affine matrix; i.e. a matrix with a dimen- * sionality of 4 where the right column has the entries (0, 0, 0, 1). * * This procedure treats the 4 by 4 matrix as a block matrix and * calculates the inverse of one submatrix for a significant perform- * ance improvement over a general procedure that can invert any non- * singular matrix: *          --        --          --          -- *          |          | -1       |    -1      | *          | A      0 |          |   A      0 | *    -1    |          |          |            | *   M   =  |          |     =    |     -1     | *          | C      1 |          | -C A     1 | *          |          |          |            | *          --        --          --          -- * *  where     M is a 4 by 4 matrix, *            A is the 3 by 3 upper left submatrix of M, *            C is the 1 by 3 lower left submatrix of M. * * Input: *   in   - 3D affine matrix * * Output: *   out  - inverse of 3D affine matrix * * Returned value: *   TRUE   if input matrix is nonsingular *   FALSE  otherwise * ***/booleanaffine_matrix4_inverse (in, out)    register  Matrix4  *in;    register  Matrix4  *out;{    register  double    det_1;              double    pos, neg, temp;#define ACCUMULATE    \    if (temp >= 0.0)  \        pos += temp;  \    else              \        neg += temp;#define PRECISION_LIMIT (1.0e-15)    /*     * Calculate the determinant of submatrix A and determine if the     * the matrix is singular as limited by the double precision     * floating-point data representation.     */    pos = neg = 0.0;    temp =  in->element[0][0] * in->element[1][1] * in->element[2][2];    ACCUMULATE    temp =  in->element[0][1] * in->element[1][2] * in->element[2][0];    ACCUMULATE    temp =  in->element[0][2] * in->element[1][0] * in->element[2][1];    ACCUMULATE    temp = -in->element[0][2] * in->element[1][1] * in->element[2][0];    ACCUMULATE    temp = -in->element[0][1] * in->element[1][0] * in->element[2][2];    ACCUMULATE    temp = -in->element[0][0] * in->element[1][2] * in->element[2][1];    ACCUMULATE    det_1 = pos + neg;    /* Is the submatrix A singular? */    if ((det_1 == 0.0) || (ABS(det_1 / (pos - neg)) < PRECISION_LIMIT)) {        /* Matrix M has no inverse */        fprintf (stderr, "affine_matrix4_inverse: singular matrix\n");        return FALSE;    }    else {        /* Calculate inverse(A) = adj(A) / det(A) */        det_1 = 1.0 / det_1;        out->element[0][0] =   ( in->element[1][1] * in->element[2][2] -                                 in->element[1][2] * in->element[2][1] )                               * det_1;        out->element[1][0] = - ( in->element[1][0] * in->element[2][2] -                                 in->element[1][2] * in->element[2][0] )                               * det_1;        out->element[2][0] =   ( in->element[1][0] * in->element[2][1] -                                 in->element[1][1] * in->element[2][0] )                               * det_1;        out->element[0][1] = - ( in->element[0][1] * in->element[2][2] -                                 in->element[0][2] * in->element[2][1] )                               * det_1;        out->element[1][1] =   ( in->element[0][0] * in->element[2][2] -                                 in->element[0][2] * in->element[2][0] )                               * det_1;        out->element[2][1] = - ( in->element[0][0] * in->element[2][1] -                                 in->element[0][1] * in->element[2][0] )                               * det_1;        out->element[0][2] =   ( in->element[0][1] * in->element[1][2] -                                 in->element[0][2] * in->element[1][1] )                               * det_1;        out->element[1][2] = - ( in->element[0][0] * in->element[1][2] -                                 in->element[0][2] * in->element[1][0] )                               * det_1;        out->element[2][2] =   ( in->element[0][0] * in->element[1][1] -                                 in->element[0][1] * in->element[1][0] )                               * det_1;        /* Calculate -C * inverse(A) */        out->element[3][0] = - ( in->element[3][0] * out->element[0][0] +                                 in->element[3][1] * out->element[1][0] +                                 in->element[3][2] * out->element[2][0] );        out->element[3][1] = - ( in->element[3][0] * out->element[0][1] +                                 in->element[3][1] * out->element[1][1] +                                 in->element[3][2] * out->element[2][1] );        out->element[3][2] = - ( in->element[3][0] * out->element[0][2] +                                 in->element[3][1] * out->element[1][2] +                                 in->element[3][2] * out->element[2][2] );        /* Fill in last column */        out->element[0][3] = out->element[1][3] = out->element[2][3] = 0.0;        out->element[3][3] = 1.0;        return TRUE;    }}

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