📄 11.txt
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Channel impulse response %
%%%%%%%%%%%%%%%%%%%%%%%%%%%%
if (Rayleigh)
N=50;
fm=100;
B=20e3;
fd=(rand(1,N)-0.5)*2*fm;
theta=randn(1,N)*2*pi;
c=randn(1,N);
c=c/sum(c.^2);
t=0:fm/B:10000*fm/B;
Tc=zeros(size(t));
Ts=zeros(size(t));
for k=1:N
Tc=c(k)*cos(2*pi*fd(k)*t+theta(k))+Tc;
Ts=c(k)*sin(2*pi*fd(k)*t+theta(k))+Ts;
end
r=ones(Mt*Mr,1)*(Tc.^2+Ts.^2).^0.5;
index=floor(rand(Mt*Mr,DS)*5000+1);
end
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