📄 hurvdemo.m
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function hurvdemo% hurvdemo --> Demonstrates high-rank URV algorithms.% <Revision>% Ricardo D. Fierro, California State University San Marcos% Per Christian Hansen, IMM, Technical University of Denmark% Peter S. K. Hansen, IMM, Technical University of Denmark%% Last revised: June 22, 1999%-----------------------------------------------------------------------fprintf(1,'. \n');fprintf(1,'. The purpose of HURVDEMO is to demonstrate \n');fprintf(1,'. the high-rank URV algorithms in HURV and \n');fprintf(1,'. HURV_A. \n');fprintf(1,'. \n');input('. [Press RETURN to continue]');fprintf(1,'. \n');format short e;% Test matrix generation.m = 50;n = 20;randn('seed',100);A = randn(m,n);numrank = 13;[u,s,v] = svd(A);s1 = 2*logspace(1,-3,numrank);s2 = 5*logspace(-4,-6,n-numrank);s(1:n,:) = diag([s1 s2]);A = u*s*v';% Define input parameters.tol_rank = 0.001;tol_ref = 1e-04;max_ref = 1;fprintf(1,'. \n');fprintf(1,'. Input parameters to HURV \n');fprintf(1,'............................................................\n');fprintf(1,'. no. rows m of A = %3.0f \n',m);fprintf(1,'. no. cols n of A = %3.0f \n',n);fprintf(1,'. rank tolerance (tol_rank) = %6.4e \n',tol_rank);fprintf(1,'. refinement tolerance (tol_ref) = %6.4e \n',tol_ref);fprintf(1,'. max refinement steps (max_ref) = %3.0f \n',max_ref);fprintf(1,'............................................................\n');fprintf(1,'. \n');fprintf(1,'. \n');fprintf(1,'. Compute the rank-revealing URV decomposition using \n');fprintf(1,'. Stewart''s algorithm: \n');fprintf(1,'. \n');fprintf(1,'. [p,R,V,U,vec] = hurv(A,tol_rank,tol_ref,max_ref) \n');fprintf(1,'. \n');input('. [Press RETURN to continue]');fprintf(1,'. \n');fprintf(1,'. wait... \n');fprintf(1,'. \n');% Compute URV.flops(0);t0 = cputime;[p,R,V,U,vec] = hurv(A,tol_rank,tol_ref,max_ref);time = cputime - t0;noflops = flops;rnorm = norm(R(1:p,p+1:n));theta = norm(V(:,1:p)'*v(:,p+1:n));phi = norm(U(:,1:p)'*u(:,p+1:m));fprintf(1,'. \n');fprintf(1,'. Output results from HURV \n');fprintf(1,'............................................................\n');fprintf(1,'. numerical rank p of A = %3.0f \n',p);fprintf(1,'. upper bound of ||R(1:p,p+1:n)|| = %6.4e \n',vec(1));fprintf(1,'. estimate of pth singular value = %6.4e \n',vec(2));fprintf(1,'. estimate of (p+1)th singular value = %6.4e \n',vec(3));fprintf(1,'. estimate of num. nullspace angle = %6.4e \n',vec(4));fprintf(1,'. estimate of num. range angle = %6.4e \n',vec(5));fprintf(1,'............................................................\n');fprintf(1,'. \n');fprintf(1,'. \n');fprintf(1,'. SVD based results \n');fprintf(1,'............................................................\n');fprintf(1,'. numerical rank p of A = %3.0f \n',numrank);fprintf(1,'. ||R(1:p,p+1:n)|| = %6.4e \n',rnorm);fprintf(1,'. pth singular value = %6.4e \n',s1(numrank));fprintf(1,'. (p+1)th singular value = %6.4e \n',s2(1));fprintf(1,'. numerical nullspace angle = %6.4e \n',theta);fprintf(1,'. numerical range angle = %6.4e \n',phi);fprintf(1,'............................................................\n');fprintf(1,'. \n');fprintf(1,'. \n');fprintf(1,'. Computational complexity of HURV \n');fprintf(1,'............................................................\n');fprintf(1,'. floating point operations = %6.4e \n',noflops);fprintf(1,'. CPU time = %6.4e \n',time);fprintf(1,'............................................................\n');fprintf(1,'. \n');input('. [Press RETURN to continue]');fprintf(1,'. \n');% Define input parameters.tol_rank = 0.001;max_iter = 5;tol_ref = 1e-04;max_ref = 1;fprintf(1,'. \n');fprintf(1,'. Input parameters to HURV_A \n');fprintf(1,'............................................................\n');fprintf(1,'. no. rows m of A = %3.0f \n',m);fprintf(1,'. no. cols n of A = %3.0f \n',n);fprintf(1,'. rank tolerance (tol_rank) = %6.4e \n',tol_rank);fprintf(1,'. no. inverse iterations (max_iter) = %3.0f \n',max_iter);fprintf(1,'. refinement tolerance (tol_ref) = %6.4e \n',tol_ref);fprintf(1,'. max refinement steps (max_ref) = %3.0f \n',max_ref);fprintf(1,'............................................................\n');fprintf(1,'. \n');fprintf(1,'. \n');fprintf(1,'. Compute the rank-revealing URV decomposition using the \n');fprintf(1,'. alternative algorithm: \n');fprintf(1,'. \n');fprintf(1,'. [p,R,V,U,vec] = hurv_a(A,tol_rank,max_iter, ... \n');fprintf(1,'. tol_ref,max_ref) \n');fprintf(1,'. \n');input('. [Press RETURN to continue]');fprintf(1,'. \n');fprintf(1,'. wait... \n');fprintf(1,'. \n');% Compute URV.flops(0);t0 = cputime;[p,R,V,U,vec] = hurv_a(A,tol_rank,max_iter,tol_ref,max_ref);time = cputime - t0;noflops = flops;rnorm = norm(R(1:p,p+1:n));theta = norm(V(:,1:p)'*v(:,p+1:n));phi = norm(U(:,1:p)'*u(:,p+1:m));fprintf(1,'. \n');fprintf(1,'. Output results from HURV_A \n');fprintf(1,'............................................................\n');fprintf(1,'. numerical rank p of A = %3.0f \n',p);fprintf(1,'. upper bound of ||R(1:p,p+1:n)|| = %6.4e \n',vec(1));fprintf(1,'. estimate of pth singular value = %6.4e \n',vec(2));fprintf(1,'. estimate of (p+1)th singular value = %6.4e \n',vec(3));fprintf(1,'. estimate of num. nullspace angle = %6.4e \n',vec(4));fprintf(1,'. estimate of num. range angle = %6.4e \n',vec(5));fprintf(1,'............................................................\n');fprintf(1,'. \n');fprintf(1,'. \n');fprintf(1,'. SVD based results \n');fprintf(1,'............................................................\n');fprintf(1,'. numerical rank p of A = %3.0f \n',numrank);fprintf(1,'. ||R(1:p,p+1:n)|| = %6.4e \n',rnorm);fprintf(1,'. pth singular value = %6.4e \n',s1(numrank));fprintf(1,'. (p+1)th singular value = %6.4e \n',s2(1));fprintf(1,'. numerical nullspace angle = %6.4e \n',theta);fprintf(1,'. numerical range angle = %6.4e \n',phi);fprintf(1,'............................................................\n');fprintf(1,'. \n');fprintf(1,'. \n');fprintf(1,'. Computational complexity of HURV_A \n');fprintf(1,'............................................................\n');fprintf(1,'. floating point operations = %6.4e \n',noflops);fprintf(1,'. CPU time = %6.4e \n',time);fprintf(1,'............................................................\n');fprintf(1,'. \n');%-----------------------------------------------------------------------% End of function hurvdemo%-----------------------------------------------------------------------
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